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qaws [65]
3 years ago
6

Factor this polynomial completely. If it will not factor, type PRIME.X^2+2X-8

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0
X^2 + 2x - 8
(x + 4)(x - 2)
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Which of the following fractions can be represented by a terminating decimal? OA 8/9 OB)13/8 OC) 4/3 OD) 6/11​
velikii [3]

Answer:

\frac{13}{8}

Step-by-step explanation:

\frac{13}{8}   \:  \: cuz \: when \: u \: simplify \: into \: a \: decimal \: would \: be \: 1.625 \\ and \: if \: u \: round \: would \: be \: 2 \: so \: u \: take \: out \: the \: decimal \:

6 0
3 years ago
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Show me how to do this problem, 5550/ 10to the 3rd power
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Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.
nadya68 [22]

Answer:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given X_(1), X_(2) ,..., X_(n) and for each observation X_i \sim N(\mu, \sigma) since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is X_(n) and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0
3 years ago
David drove 20 miles in 5 mins. Sean drove 45 miles in 9 mins. Who drove at a faster rate? Explain.
mars1129 [50]
Sean drove at a faster rate because if you divide each miles/minutes then it gives you how many miles per minute they drive. 20/5 is 4, and 45/9 is 5, and 5 is greater than 4.
6 0
3 years ago
Please help :((<br> fillerfillerfiller
snow_tiger [21]

Answer:

1,385.442360233099

Step-by-step explanation:

Pie times the radius squared

6 0
3 years ago
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