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It’s gonna be all real numbers (-infinity, infinity) because it goes through all the points. And because there’s no restrictions
Answer:
Explanation:
So you want to start by finding the area of the big square.
We know the width to the big square is 60cm. The length to the big square is
19
+
24
+
13
=
56
Big square
A
r
e
a
=
L
⋅
W
=
56
⋅
60
=
3360
Now let’s find the little square inside the bigger square. We see from the picture that the width is 34 and the length is 24cm. Using the same formula, we can find the area of the little square.
Little square
A
r
e
a
=
L
⋅
W
=
24
⋅
34
=
816
The area enclosed is the area of the big square minus the area of the little square.
3360
−
816
=
2544
So the area enclosed is
2544
c
m
2
Step-by-step explanation:
Answer:
= 105(x+2)/33-x
Step-by-step explanation:
Given the expression
[3(x+2)*10*7]÷70 - 2(x+2)
= 3(x+2)*70÷70 - 2(x+2)
= 210(x+2)/70-2x-4
= 210(x+2)/66-2x
= 210(x+2)/2(33-x)
= 105(x+2)/33-x
The third one because its the only one decreasing
