The probability of picking 2 white balls and 1 black ball is 0.154
<h3>How to determine the probability?</h3>
The given parameters are:
- Number of balls, n = 20
- White = 12
- Black = 8
When each ball is selected, the total number of ball decreases by 1 and the type of ball also decreases.
So, the probability is represented as:
P(2 white and 1 black) = White/n * White - 1/n - 1 * Black//n - 2
Substitute known values
P(2 white and 1 black) = 12/20 * 11/19 * 8//18
Evaluate
P(2 white and 1 black) = 0.154
Hence, the probability of picking 2 white balls and 1 black ball is 0.154
Read more about probability at:
brainly.com/question/251701
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Answer:
{3xl42}
Step-by-step explanation:
Answer:
x = -3. Y = 12
Step-by-step explanation:
the answer is D
Answer:
Step-by-step explanation:
Given expression is:
![(\sqrt[8]{x^7} )^{6}](https://tex.z-dn.net/?f=%28%5Csqrt%5B8%5D%7Bx%5E7%7D%20%29%5E%7B6%7D)
First we will use the rule:
![\sqrt[n]{x} = x^{\frac{1}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D)
So for the given expression:
![\sqrt[8]{x^{7}}=(x^{7} )^{\frac{1}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bx%5E%7B7%7D%7D%3D%28x%5E%7B7%7D%20%29%5E%7B%5Cfrac%7B1%7D%7B8%7D%20%7D)
We will use tha property of multiplication on powers:
Applying the outer exponent now
