write a quadratic function f(x) for the area of a rectangle with a length of x + 5 and a width of 3x - 7

1 answer:

3 0

Hello,

What is the problem ?

f(x)=(x+5)(3x-7)=3x²+8x-35

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BigorU [14]

<span>(2x + y2)<span>5 heres you answer your so welcome</span></span>

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Yuri [45]

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3 years ago

melisa1 [442]

Answer: It should be 3w - 6y + 3

Step-by-step explanation:

-Solve:

$2(w-3y+4)+w-5$

-Use Distributive Property:

$2(w-3y+4)+w-5$

$2w-6y+8+w-5$

-Then, combine like terms:

$2w-6y+8+w-5$

$3w-6y+3$

Result:

$3w-6y+3$

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3 years ago

igor_vitrenko [27]

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3 years ago

qwelly [4]

The answer to your question is 503

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3 years ago