<h2>Given :- </h2><h2 />
- Side of the square field = 70m
- Length of the rectangular field = 90m
- Breadth of the rectangular field = 60m
<h2>To Find :-</h2>
- Perimeter of the square field
- Perimeter of the rectangular field
<h2>Solution :-</h2>
Perimeter of the square = 4 × side
By substituting values,
⇒ 4 × 70m
➥ 280m
<h3><u>Hence, </u><u>Faliha</u><u> runs 280m around a Square </u><u>field</u></h3>
Perimeter of the rectangle = 2( length + Breadth)
By substituting values,
⇒ 2( 90m + 60m )
⇒ 2( 150m)
➥ 300m
<h3><u>Hence, Rameen runs 300m around a rectangular field</u></h3>
By comparing perimeters, Rameen runs more than Faliha
Distance runs more by rameen = Distance covered by rameen - distance covered by faliha
By substituting values,
⇒ 300m - 280m
➠ 20m
<h3><u>Hence, </u><u>Rameen</u><u> runs more around a rectangular field by 20</u><u>m</u></h3>
<u>
</u>
D + 5 >= 17
We can subtract 5 from each side:
d >= 12
To get 20 on the right, we have to add 8 to each side (20-12=8).
d + 8 >= 20
To get d - 5 from the first expression (d + 5 >= 17) we have to subtract ten from each side (5-10=-5) and we get:
d - 5 >= 7
Answer:
x = - 
, x = - 1
Step-by-step explanation:
Given
(x + 1)(3x + 4) = 0
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = -
Solutions from least to greatest are
x = - , x = - 1
1/6+2/3+1/4
First find the highest common multiple of the denominators=12
Then multiply each term by the quotient of 12/denominator
So...it becomes 2/12+8/12+3/12
Add all the numerators and keep the denominator constant
It becomes (2+8+3)/12=13/12
=1 1/12
I hope this explains it:
(Work and info in attachment)
