Answer:
90% is the answer for confidence interval
Step-by-step explanation:
Given that a field test for a new exam was given.75±0.05(75)
i.e. margin of error =0.05(75)=
The population under study was the seniors. Sample mean and std dev were calculated
Stated that the exam creator ased on the results, that on the same exam, 9 out of 10 seniors will have an average score within 5% of 75%
This implies that 9 out of 10 means in percent 90%
Hence the confidence interval is 90%
SInce 5% of 75 is given the range is 75±(75)
Margin of error =3.75
Confidence interval =(75±3.75)
=(71.25,78.75)
We can interpret this we are 90% confident that as sample sizes increase, and samples are drawn at random the average grades of seniors would lie between 71.25 and 78.75
(18,27), because the rate of change of the function is 4/3( answer B)
Answer:
Step-by-step explanation:
Answer:
f=11
Step-by-step explanation:
If t=7, we can substitute it into the original equation:
f=(2)(7)-3
Simplify:
f=14-3
f=11
<em>~Stay golden~ :)</em>
Answer:
48
Step-by-step explanation:
pq
substitute values
(8)(6)
8*6 = 48