Question

Hepl will give branliest​

Answer 1

Answer:

1

I THINK I GOT IT OMG THAT WAS SO HARD

Answer 2

Answer:

z = 5

Step-by-step explanation:

$\frac{4x^2y^7}{8x^3y^2} = \frac{y^z}{2x}$

It can be also written as -

$\frac{2^2 \times x^2 \times y^7}{2^3 \times x^3 \times y^2} = \frac{1 \times x^0 \times y^z}{2 \times x^1 \times y^0}$

Using law of exponents , lets solve this.

$=> 2^{(2-3)} \times x^{(2-3)} \times y^{(7 - 2)} = \frac{1}{2} \times x^{(0-1)} \times y^{(z-0)}$

$=> 2^{-1} \times x^{-1} \times y^{5} = 2^{-1} \times x^{-1} \times y^z$

$=> \frac{y^5}{2x} = \frac{y^z}{2x}$

$=> y^z = y^5$

$=> z = 5$