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Thepotemich [5.8K]
3 years ago
13

For an in-class demonstration, a teacher flips a fair coin 5 times, and each of the 5 times it lands on heads. A student argues

that it's more likely to land on tails on the next flip. What, if anything, is incorrect about the student's logic?
A.
The student's logic is incorrect; since a coin being flipped 5 times is 5 independent events, the probability of the next flip landing on heads is still 1/2.
B.
The student's logic is incorrect; since a coin being flipped 5 times is 5 dependent events, the probability of the next flip landing on heads is still 1/2
C.
There is nothing wrong with the student's logic; because a coin being flipped 5 times is 5 independent events, the probability the next flip will land on heads is affected by the previous outcomes.
D.
There is nothing wrong with the student's logic; because a coin being flipped 5 times is 5 dependent events, the probability the next flip will land on heads is affected by the previous outcomes.
Mathematics
1 answer:
Hoochie [10]3 years ago
3 0
A appears to be correct

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12345 [234]

Given that 2 large puzzle costs $16 then

2l=16

or

l=8

That means cost of 1 large puzzle = $8


Given that 3 small puzzle costs $15 then

3s=15

or

s=5

That means cost of 1 small puzzle = $5


Now we will use this information to find the correct choice.

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First choice is <u>wrong </u>as coefficient 8 is with 8l so that gives cost of 1 large not small puzzle.

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Second choice is <u>correct </u>as coefficient 8 is with 8l so that gives cost of 1 large puzzle.

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Third choice is <u>correct </u>as coefficient 5 is with 5s so that gives cost of 1 small puzzle.

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Fourth choice is <u>Wrong </u>as coefficient 5 is with 5s so that gives cost of 1 small not large puzzle.

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Fifth choice is <u>wrong </u>as constant 128 gives total cost of not the total number of puzzles.



5 0
3 years ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

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4 years ago
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fredd [130]

Where is the question?

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maria [59]
Answer:
2.25

Explanation:
1 1/2 * 1 1/2 * 1 = 2.25 or 2 1/4
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Step-by-step explanation:

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