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Svetlanka [38]
4 years ago
15

What is the area of this trapezoid? a. 108 in2 b. 139.5 in2 c. 166 in2 d. 171

Mathematics
1 answer:
Vikentia [17]4 years ago
6 0

Answer:

B. 139.5 in2

Step-by-step explanation:

22.5 = CEB

108 = FEAB

9= DFA

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The function table shown matches y = 2x + 4. Find the missing value in the table.
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y=2x+4

-4 -4

-4=2x

-4/2 2x/2

-2=x

Im not 100% sure if this is correct.

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3 years ago
M2-37m+52-35m2+42m ​
GREYUIT [131]

Answer:

idk

Step-by-step explanation:

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4 0
4 years ago
The length of a cell phone is 1.21.2 inches and the width is 4.64.6 inches. The company making the cell phone wants to make a ne
Reika [66]

Answer:

<em>The width of the new phone will be 4.37 inches</em>

Step-by-step explanation:

<u>Proportions</u>

A direct proportion is a relation between variables where their ratio is a constant value.

The original length of a cell phone was L=1.2 inches and the original width was 4.6 inches.

A new version of the cell phone is to be released with proportional dimensions with respect to the original cell phone.

We are given the length of the new phone L'=1.14 inches. The ratio of the lengths is 1,2/1.14=1.053.

The new width should be W'=4.6/1.053=4.37 inches

The width of the new phone will be 4.37 inches

3 0
3 years ago
I need to find q, r, s, t <br> The function is g(x)=2x^2-8
Shalnov [3]

Answer:

q=0

r=2

s=3

t=-3

Step-by-step explanation:

q represents the value we should get from evaluating d(-8).

d(x)=-\sqrt{\frac{1}{2}x+4}

To find d(-8) we use this function here labeled d and replace x with -8:

d(-8)=-\sqrt{\frac{1}{2}(-8)+4}

d(-8)=-\sqrt{-4+4}

d(-8)=-\sqrt{0}

d(-8)=0

So q is 0 since d(-8)=0.

r represents the value we should get from evaluating f(0).

f(x)=\sqrt{\frac{1}{2}x+4}

To find f(0) we use this function labeled f and repalce x with 0:

f(0)=\sqrt{\frac{1}{2}(0)+4}

f(0)=\sqrt{0+4}

f(0)=\sqrt{4}

f(0)=2

So r is 2 since f(0)=2.

s represents the value we should get from evaluating f(10).

f(x)=\sqrt{\frac{1}{2}x+4}

To find f(10) we use this function labeled f and replace x with 10:

f(10)=\sqrt{\frac{1}{2}(10)+4}

f(10)=\sqrt{5+4}

f(10)=\sqrt{9}

f(10)=3

So s is 3 since f(10)=3.

t represents the value we should get from evaluating d(10).

d(x)=-\sqrt{\frac{1}{2}x+4}

To find d(10) we use the function labeled d and replace x with 10:

d(10)=-\sqrt{\frac{1}{2}(10)+4}

d(10)=-\sqrt{5+4}

d(10)=-\sqrt{9}

d(10)=-3

So t is -3 since d(10)=-3

q=0

r=2

s=3

t=-3

8 0
3 years ago
Point D is located at (7,1). What are the coordinates of Point D after a Vertical Stretch of 3?
densk [106]

Answer:

since it got stretched by 3 it's 4

5 0
3 years ago
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