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SVEN [57.7K]
2 years ago
13

Which of the following satisfy x ≥ 4.1? Select all that apply.

Mathematics
1 answer:
natta225 [31]2 years ago
3 0

Answer:

x = 4.5

x = 4.1

Step-by-step explanation:

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Mariulka [41]

Answer:

7.7

Step-by-step explanation:

square root 59 and it's 7.681, round to tenth to get 7.7

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2 years ago
Plzzzzzzzzzzzzzzzzzz help quick
Bezzdna [24]

Answer:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is  \frac{-6-0}{6-5} ⇒ C

Step-by-step explanation:

The formula of the slope of a line passes through points (x_{1},y_{1}) and (x_{2},y_{2})

is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The line passes through points (5 , 0) and (6 , -6)

∴ x_{1} = 5 and  x_{2} = 6

∴  y_{1} = 0 and  y_{2} = -6

Substitute these values in the formula of the slope

∵ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∴ m=\frac{-6-0}{6-5}

Let us look to the answer and find the same formula

The answer is:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is  \frac{-6-0}{6-5}

8 0
3 years ago
Someone help, the question is on the attachment.​
gavmur [86]
The answer is y = 2.
6 0
3 years ago
the point (2,3) is in the terminal side of an angle theta, in standard position. what are the values of sine, cosine, and tangen
suter [353]
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13

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8 0
3 years ago
A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the per
nekit [7.7K]

Answer:

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

6 0
3 years ago
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