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tankabanditka [31]

2 years ago

15

What is the slope of the tangent line through (3,2) and (x,y) for x=-2 and y=x3

1 answer:

Allushta [10]2 years ago

3 0

First you must derive the equation to find the slope:
y = x ^ 3
y '= 3x ^ 2
Then, for x = -2 we have the slope is:
y '(- 2) = 3 (-2) ^ 2 = 12
Then the equation of the line with slope equal to 12 and passing through point (3,2) is:
y = 12 (x-3) +2

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Solve the following equation and show all the steps to solving.

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8 0

3 years ago

Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of z0 = 5i.

Agata [3.3K]

3 because the 2z minus the 3 gives you 1 rounded

4 0

3 years ago

Read 2 more answers

Find the value of x plz i will mark brainliest

irinina [24]

Answer:

x=30

Step-by-step explanation:

Angle sum in a triangle=180

x+3x+2x=180

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x=30

4 0

2 years ago

Read 2 more answers

Please help me with this please and thank you

rjkz [21]

Answer:

Alright so the answer is B but I'll explain why because im nice ig.

Step-by-step explanation:

So lets do some calcumalations.

We'll use 1 as n and should get an output of 3 to check these formulas. Since 1 is the first term and 3 is the first term value makes sense alright.

So 9^1-1 is 0 and any number to the 0 power is 1 so that wont work.

3(4)^1-1 = 3(1); that's the answer

4^1-1 = 1, + 3 = 4 so that wont work either

I hope this helps ya have a great afternoon

8 0

2 years ago

Can someone please help me with this? ASAPPP

adoni [48]

<h2>43 cm.</h2>

Hope it helps you!

-miraculousfanx-

7 0

3 years ago