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3 years ago

What is the slope of the tangent line through (3,2) and (x,y) for x=-2 and y=x3

1 answer:

3 0

First you must derive the equation to find the slope:
y = x ^ 3
y '= 3x ^ 2
Then, for x = -2 we have the slope is:
y '(- 2) = 3 (-2) ^ 2 = 12
Then the equation of the line with slope equal to 12 and passing through point (3,2) is:
y = 12 (x-3) +2

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Step-by-step explanation:

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Final Answer: $-12x + 1.5$

Steps/Reasons/Explanation:

Question: Which expression is equivalent to $-3(4x - 0.50)?$

Step 1: Expand by distributing terms.

$-3$ × $4x - 3$ × $-0.50$

Step 2: Simplify $-3$ × $4x$ to $-12x$ .

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Step 3: Simplify $3$ × $-0.50$ to $-1.5$ .

$-12x - (-1.5)$

Step 4: Remove parentheses and add.

$-12x + 1.5$

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Step-by-step explanation:

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