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3 years ago

Question 1 (50 points)

Mathematics

1 answer:

Lena [83]3 years ago

3 0

Answer:

Step-by-step explanation:

guess i will do Q.2 first

f(x)=2x+1 n g(x)=2x^2+1,

at x=0, f(0)=1=g(0)

x=1, f(1)=3=g(1)

in general a straight line like f(x) and a parabola like g(x) will intersect at most 2 times. in this case, at x=0 n 1.

x=3, f(3)=2(3)+1=7, g(3)=2(3)^2+1=19

f(x)<>g(x) at x=3

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Answer:

Large box weighs 18.25 kilograms

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Step-by-step explanation:

A fruit company delivers its fruit in two types of boxes: large and small.

Let x = weight of large box.

Let y = weight of small box.

A delivery of 3 large boxes and 5 small boxes has a total weight of 131 kilograms. This means

3x + 5y = 131 - - - - - - - - - - -1

A delivery of 6 large boxes and 2 small boxes has a total weight of 140 kilograms.

This means 6x + 2y = 140 - - - - - - - 2

Solving equation 1 and equation 2 by elimination method,

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18x + 30y = 786

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24y = 366

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Put y = 15.25 in equation 1

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3 years ago

Two mechanics worked on a car. The first mechanic charged S95 per hour, and the second mechanic charged S115 per hour.

Norma-Jean [14]

The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.

Step-by-step explanation:

Given,

Charges of first mechanic = $95 per hour

Charges of second mechanic = $115 per hour

Total hours = 25

Total amount charged = $2675

Let,

The number of hours worked by first mechanic = x

The number of hours worked by second mechanic = y

According to given statement;

x+y=25 Eqn 1

95x+115y=2675 Eqn 2

Multiplying Eqn 1 by 95

$95(x+y=25)\\95x+95y=2375\ \ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

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Dividing both sides by 20

$\frac{20y}{20}=\frac{300}{20}\\y=15$

Putting y=15 in Eqn 1

$x+15=25\\x=25-15\\x=10$

The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

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Answer:

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