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3 years ago

Help!! What's the answer for his problem?

Mathematics

2 answers:

meriva3 years ago

4 0

Break it into three sections, then solve for the respective volumes of the three boxes. Your answer is 200cm^3

pashok25 [27]3 years ago

3 0

The answer is 200cm^3

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Rewrite algebraic expression for 3(y+10)

wel

I think that the answer is 3Y+30. I hope this helps!!! :)

3 0

3 years ago

The equation of a line is y-4=3(x+2) , which of the following is a point on the line?

kramer

Y-4=3(x+2)
y-4=3x+6

y = 3x +10

so in case of choise C. we get

4 = 3*(-2) +10

4 = -6 +10

4 = 4

hope this will help you

8 0

3 years ago

Based only on the given information, it is guaranteed that AB 1 CD

Roman55 [17]

Answer:

true

Step-by-step explanation:

the answer is true just got done working on my son's math homework hey work that he's working these out as well he said it was true

5 0

2 years ago

HELP NEEDED IN MATHS

Nata [24]

30-2q=16
-2q=16-30
-2q=-14
q=7

7 0

3 years ago

Many companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whethe

s2008m [1.1K]

Answer:

There is enough evidence to support the claim that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent (P-value = 0.01537).

Step-by-step explanation:

<em>The question is incomplete: the picture attached gives the missing sample data.</em>

This is a hypothesis test for the difference between proportions.

The claim that is going to be stated in the alternative hypothesis is that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent. This means that the proportions differ significantly.

Then, the null and alternative hypothesis can be written as:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1 (Male celebrity), of size n1=150 has a proportion of p1=0.273.

$p_1=X_1/n_1=41/150=0.273$

The sample 2 (Female celebrity), of size n2=150 has a proportion of p2=0.407.

$p_2=X_2/n_2=61/150=0.407$

The difference between proportions is (p1-p2)=-0.133.

$p_d=p_1-p_2=0.273-0.407=-0.133$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{41+61.05}{150+150}=\dfrac{102}{300}=0.34$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.34*0.66}{150}+\dfrac{0.34*0.66}{150}}\\\\\\s_{p1-p2}=\sqrt{0.001496+0.001496}=\sqrt{0.002992}=0.055$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.133-0}{0.055}=\dfrac{-0.133}{0.055}=-2.44$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(z$

As the P-value (0.01537) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of brand awareness of female TV viewers and the gender of the spokesperson are not independent (the proportions differ).

6 0

2 years ago