There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
B
Step-by-step explanation: it is easy
If point A is between B and C, then CA+AB = CB by the segment addition postulate. This is the idea of taking two smaller segments to "glue" them together to form a larger segment. Or you can think in reverse: take some larger segment and split it somewhere in between the endpoints (not necessarily the halfway point), this will produce two smaller segments.
For example: you have a ruler that is 12 inches. Take a saw and cut the ruler at the "2 inch" marker. You'll end up with two smaller pieces of plastic: one of which is 2 inches, the other 10 inches. The two smaller pieces can be taped together to reform the original 12 inch ruler.
Answer: The third choice.
Step-by-step explanation: To find the first output, start with your first input. In this case, it's -2, so your equation would be g(-2)= -1/2(4(-2)+6). Start by solving inside the parenthesis. 4x-2=-8 and -8+6=-2. -1/2x-2= 1, so your first output should be 1. The only choice that has this is the third one, so that is your answer. Hope I could help :)
