Answer:
1. Western erodes 2 ft/yr; Dunes builds up at 5 ft/yr
2. Sometime in 2006
3. Solve simultaneous equations
Step-by-step explanation:
1. Erosion patterns
(a) Western Beach
In 15 yr, Western Beach erodes from 100 ft to 70 ft.
The rate of erosion is 30 ft/15 yr = 2 ft/yr.
(b) Dunes Beach
In 15 yr, Dunes Beach builds up from 20 ft to 95 ft.
The rate of buildup is 75 ft/15 yr = 5 ft/yr.
2. Beaches with equal width
From the table, it appears that the beaches will have the same width sometime in year 11 (2006).
3. Best approximation
The graph below also shows that it happens part way through year 11 (2006).
We could get an even better solution by calculating the equations of the two lines and solving the simultaneous equations.
Answer:
<h3>
f(x) = 4(x - 4)² - 4 </h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - vertex form of the equation of the parabola with vertex (h, k)
so the equation of parabola with the vertex (4, -4) is
f(x) = a(x - 4)² - 4
passes through the point (2, 12) means if x=2 then f(x)=12
12 = a(2 - 4)² - 4
12 +4 = a(-2)² - 4 +4
16 = 4a
a = 4
Therefore the equation (in vertex form) of parabla is:
<u> f(x) = 4(x - 4)² - 4 </u>
N- a number
The sum of 18 and a number: 18 + n
Divide -5/8 by .5 which is uhmm..
Answer: 133.69 or 133.7
Step-by-step explanation: