A = Ao(x)^t
Ao = 500
A = 500(x)^t
400 = 500 (x)^1
x = 4/5
A = 500(4/5)^t << The exp eqn
He bought 200 of them
200*2.80=$560
marked up 90%
90% of 560=0.9*560=504
560+504=1064
he sold all 200 for a total of 1064, or an average price of $5.32 each
PQRS is an isosceles trapezoid and m < Q=127
so m<Q = m<P =127
answer
127
$59.40 was the original price for the shoes
Answer: c).
Both options are true. You can see that the whiskers of data set 2 (The lines extending on either side of the box plots) represent a much larger range of data than data set 1, and that the median in data set 2 (the line down the middle of the boxes) is greater than data set 1.
Hope this helps!
