The answer is:
E per gram = 0.45 V
The explanation:
when MnO2 is the substance who oxidized here so, the oxidizing agent and the anode here is Li.
and when the molar mass of Li is = 7 g/mol
and in our reaction equation we have 1 mole of Li will give 3.15 V of the electrical energy
that means that :
7 g of Li gives → 3.15 V
So 1 g of Li will give→ ???
∴ The E per gram = 3.15 V / 7 g of Li
= 0.45 V
Answer:
<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>
Explanation:
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<em>Mean = 14.2 or 14</em>
<em>Median = 14</em>
<em>Mode = 16</em>
<em>Range = 6</em>
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<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>
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<em>Hope this helps! <3</em>
<em>__________________________________________________________</em>
Answer:
4.4 mol.
Explanation:
Hello!
In this case, since the formula for calculating the molarity is:

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

Thus, we plug in the given data to obtain:

Best regards!