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Bond [772]
3 years ago
6

Which figure has line symmetry and point symmetry a)trapezoid b)quadrilateral c)pentagon d)square

Mathematics
2 answers:
kvasek [131]3 years ago
7 0
A quadrilateral because there sides and points are symmetrical.
alexdok [17]3 years ago
4 0
The square is the only one with both point and line symmetry.
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Write two numbers, neither of which is 8, whose GCF is 8.
elena-14-01-66 [18.8K]
128 and 16 GCF is 8
8 0
3 years ago
I need help!! on 9 and 10 plzz help
Alexxandr [17]

9.      1/3+(x+20)+(x-10)+40=360           10.   1/2x+1/2x+(x-15)+(x-25)+100=540

          1/3+2x+50=360                                  4x+60=540

          (3/1) 1/3+2x=300(3/1)                           4x/4=480/4

          2x=300                                                X=120

           ————

               2

W=150

6 0
3 years ago
Please can someone solve this question?
kaheart [24]
4 x 4 x 4 thats all ☺

7 0
3 years ago
Find two numbers that have a sum of 4 and a product of -5
nekit [7.7K]

Answer:

-1 and 5

Step-by-step explanation:

7 0
3 years ago
I have 10 goats, n of which are male. I need to choose 2 of them to make a casserole.
snow_tiger [21]

Answer: There are 4 male goats.

Step-by-step explanation:

We know that n of the 10 goats are male.

The probability that in a random selection, the selected goat is a male, is equal to the quotient between the number of male goats (n) and the total number of goats (10)

The probability is;

p = n/10

Now the total number of goats is 9, and the number of male goats is n -1

then the probability of selecting a male goat again is:

q = (n-1)/9

The joint probability (the probability that the two selected goats are male) is equal to the product of the individual probabilities, this is

P = p*q = (n/10)*((n-1)/9)

And we know that this probability is equal to 2/15

Then we have:

(n/10)*((n-1)/9) = 2/15

(n*(n-1))/90 = 2/15

n*(n-1) = 90*2/15 = 12

n^2 - n = 12

n^2 - n - 12  = 0

This is a quadratic equation, we can find the solutions if we use Bhaskara's formula:

For an equation:

a*x^2  + b*x + c =  0

The two solutions are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

For our case, the solutions will be:

n = \frac{1 +- \sqrt{(-1)^2 - 4*1*(-12)} }{2*1 } = \frac{1+- 7}{2}

The two solutions are:

n = (1 - 7)/2 = -3    (this solution does not make sense, we can not have a negative number of goats)

The other solution is:

n = (1 + 7)/2 = 4

This solution does make sense, this means that we have 4 male goats.

5 0
3 years ago
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