The first one seems the most correct
The right answer is Haploid cells join to form an organism that has a complete set of chromosomes.
Meiosis makes it possible to pass from a cell to 2n chromosomes to 4 cells with n chromosomes, thus ensuring the passage from the diploid phase to the haploid phase.
So from the fertilization phase to the meiosis phase, the cells will be diploid (2n chromosomes). From the meiosis phase to the fertilization phase, it is the haploid phase (n chromosome).
Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
Answer:
- She does not carry the gene for cystic fibrosis.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
Answer:
I don't know
Explanation:
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1 Both types of succession require the same amount of time to occur.
2 Both types of succession result in greater biodiversity over time.
3 Both types of succession decrease the stability of an ecosystem.
4 Both types of succession have the same starting conditions.
5 Both types of succession eventually lead to a community closer to equilibrium.
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