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In-s [12.5K]
4 years ago
10

Adam is 10 years old. Mr. Collins is 3 times as old as Adiam. Which model

Mathematics
1 answer:
dezoksy [38]4 years ago
8 0

Answer:

The age of Mr. Collins is 30 years and

The model which represent the problem is, The age of Mr. Collins is         3  × 10

Step-by-step explanation:

Given as :

The age of Adam = 10 years

The age of Mr. Collins = x years

The age of Mr. Collins = 3 times the age of Adam

Or, x = 3 × The age of Adam

Or, x =  3 × 10

∴  x = 30

So, The age of Mr. Collins = x years = 30 years

The model which represent the problem is, The age of Mr. Collins = 3  × 10

Hence The age of Mr. Collins is 30 years and

The model which represent the problem is, The age of Mr. Collins = 3  × 10

Answer

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Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is
FinnZ [79.3K]

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Further explanation:

Given:

Vector a is \vec a = 4.00\hat i + 7.00\hat j.

Vector b is \vec b = 5.00\hat i - 2.00\hat j.

Explanation:

The cross product of a \times b can be obtained as follows,

\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}

The vector can be expressed as follows,

a \times b =  - 43\hat k

The magnitude of a \times bcan be obtained as follows,

\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}43404

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

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3 years ago
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find the area of a triangular shaped land having the length of three sides 20,34 M and 42 respectively in metre square Anna and
matrenka [14]

Step-by-step explanation:

if I understand you correctly, then the 3 sides are

a = 20 m

b = 34 m

c = 42 m

under this assumption the best is to use Heron's Formula to get the area :

s = (a + b + c)/2

area = sqrt(s(s - a)(s - b)(s - c))

in our case

s = (20 + 34 + 42)/2 = 96/2 = 48

area = sqrt(48(48-20)(48-34)(48-42)) =

= sqrt(48×28×14×6) = sqrt(112,896) =

= 336 m²

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Solve the system of equations by substitution.<br><br> y = 4x -1<br><br> 2x + 2y = 3
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Answer:

(0.5, 1)

Step-by-step explanation:

Using Desmos Graphing calculator, I put both of these equations in, found where the lines intersected, and saw that the ordered pair I was left with was:

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3 years ago
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Two quadrilaterals are similar. The length of the row longest sides of the first quadrilateral are 40in and 60in. The lengths of
Andreyy89

Answer:

The sides of the first quadrilateral are 60 in, 40 in, 30 in and 12,5 in

The sides of the second quadrilateral are 24 in, 16 in, 12 in and 5 in

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

Arrange the sides of each quadrilateral from largest to smallest

<u><em>First quadrilateral </em></u>            <u><em>Second quadrilateral</em></u>

Longest side=60 in          Longest side=c in

Second side=40 in           Second side=16 in

Third  side= a in                Third  side= 12 in

Fourth side=b in                Fourth side=5 in

so

\frac{60}{c}=\frac{40}{16}=\frac{a}{12}=\frac{b}{5}

<em>Find the value of c</em>

\frac{60}{c}=\frac{40}{16}

c=60(16)/40

c=24\ in

<em>Find the value of a</em>

\frac{40}{16}=\frac{a}{12}

a=40(12)/16

a=30\ in

<em>Find the value of b</em>

\frac{40}{16}=\frac{b}{5}

b=40(5)/16

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Use 10 dots to secure your answer
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