Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
The probability that conservative party wins all 3 seats is 0.216
The probability that conservative party wins exactly two seats is 0.432
Step-by-step explanation:
Consider the provided information.
The probability of a conservative candidate winning is p=0.6.
The probability of one progressive candidate will win is: 1-0.6=0.4
Part (a) What is the probability that the conservative party wins all three seats?
According to binomial distribution: 



P(conservative party wins all 3 seats) = 0.216
Hence, the probability that conservative party wins all 3 seats is 0.216
Part (a) What is the probability that the conservative party wins exactly two seats?



Hence, the probability that conservative party wins exactly two seats is 0.432
we need help? can somebody answer this question
Answer:
6/7
Step-by-step explanation:
multiply the 1 by 6 and put that over 7