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3 years ago

(-2q^4)(-8q^3b^6)help I need to simplify this problem

1 answer:

Montano1993 [528]3 years ago

4 0

Multiply the constants. Multiply the variables according to the rules of exponents.
$(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}$

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Step-by-step explanation:

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2 years ago

The sum of squares of two consecutive odd numbers is 514 find the numbers

amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

$\rule{130}1$

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

$\rule{130}1$

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup$

When,

$\bullet\: \textsf {x = } \textbf {15}$

$\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}$

$\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.$

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3 years ago

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If <span>∆QRS≅∆TUV, Their corresponding sides would be equal so,
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In short, Your Answer would be Option B

Hope this helps!</span>

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3 years ago

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Step-by-step explanation:

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2 years ago

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3 years ago