Answer:34.93
Step-by-step explanation:
Using a^2+b^2=c^2we can substitute a and b in which is 34^2+8^2=c^21156+64=c^21220 = c^2Now we need to square both sides√1220 = √c^234.9284983931 ----> 34.9334.93 = cc = 34.93
A is the closest I got. My answer was 32.665 using thousandth place. I found the perimeter by adding up the lengths. I found all of the lengths by using pathat oran theorem.
Answer:

Step-by-step explanation:
The time constant of the isotope is:


The decay of the isotope is described by the following model:

Now, the time is cleared in the equation:



Equation for this line is y = -2x + (-4)
<u>Step-by-step explanation:</u>
Step 1:
Slope intercept equation for a line is of the form y= mx + b, where m is the slope and b is the y-intercept.
Step 2:
Calculate slope of the given line.
⇒ m = (y2 - y1)/(x2 - x1) = (2 - (-2))/(-3 - (-1)
⇒ m = 4/-2 = -2
Step 3:
Find y-intercept
⇒ b = - 4
Step 4:
Substitute values to get equation
⇒ y = -x -4 or y = - (x + 4)