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3 years ago

How many models of 100 do you need to model 3,200 explain

Mathematics

2 answers:

kirza4 [7]3 years ago

7 0

For this case, the first thing we must do is define a variable.

We have then:

x: number of models of 100

We now write the equation that models the problem:

$100x = 3200$

From here, we clear the value of x.

We have then:

$x =\frac{3200}{100}$

$x = 32$

Therefore, 32 models of 100 are needed to model 3,200.

Answer:

32 models of 100 are needed to model 3,200.

Neko [114]3 years ago

3 0

Change the word problem to math. Think, how many 100s can go in 3,200? So, 3,200 divided by 100. Take out the two zeros, you are left with 32. So, 32 models of 100 can go in 3,200.

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8k + 2m = 3m + k Solve for k

mina [271]

Minus both sides by 2m
$8k = 3 m - 2m + k \\ 8k = m + k$
Minus both sides by k
$7k = m$
Divided both sides by 7
$k = \frac{m}{7}$

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3 years ago

A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha

lesantik [10]

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

8 0

3 years ago

Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX is translated 4 units right and 3 uni

guapka [62]

Okay, so first of all, if the trapezoid was translated right 4,
Then all the (x)'s should be 4 more than the original value
For example: (2,-3) → (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) → (2,-6)
Now do this to all the Vertices
 $(6,-6)(8,-6)(9,-5)(5,-5)$
Final Answer: Option 2

7 0

3 years ago

Read 2 more answers

Ella has 0.5 lb of sugar. how much water should she add to make the following concentrations? Tell Ella how much syrup she will

makkiz [27]

Answer:

For 50% syrup, add 0.5 lb of water for 1 lb of syrup; for 5% syrup, add 9.5 lb of water for 10 lb of syrup; for 75% syrup, add 0.17 lb of water for 0.67 lb of syrup; for 1.5% syrup, add 32.8 lb of water for 33.3 lb of syrup.

Step-by-step explanation:

Let x represent the amount of water added. This means the total mass of the syrup is represented by 0.5+x.

To find percentages, we divide the part by the whole. For a 50% syrup, we need the part (sugar) compared to the whole (sugar + water) to equal 50%, or 0.50:

Multiply both sides by 0.5+x:

Using the distributive property, we have

0.5 = 0.5(0.5)+0.5(x)

0.5 = 0.25+0.5x

Subtract 0.25 from each side:

0.5-0.25 = 0.25+0.5x-0.25

0.25 = 0.5x

Divide both sides by 0.5:

0.25/0.5 = 0.5x/0.5

x = 0.5

For 50% syrup, add 0.5 lb of water. This makes the total mass 0.5+0.5 = 1 lb.

For 5% syrup, we change the equation to equal 0.05 (5% = 5/100 = 0.05) and leave everything else the same:

Multiply both sides by 0.5+x:

Using the distributive property,

0.5 = 0.05(0.5)+0.05(x)

0.5 = 0.025 + 0.05x

Subtract 0.025 from both sides:

0.5-0.025 = 0.025+0.05x-0.025

0.475 = 0.05x

Divide both sides by 0.05:

0.475/0.05 = 0.05x/0.05

x = 9.5

For 5% syrup, add 9.5 lb of water; the total mass will be 9.5+0.5 = 10 lb.

For 75% syrup, set the equation equal to 0.75:

Using the distributive property,

0.5 = 0.75(0.5)+0.75(x)

0.5 = 0.375 + 0.75x

Subtract 0.375 from each side:

0.5 - 0.375 = 0.375 + 0.75x - 0.375

0.125 = 0.75x

Divide both sides by 0.75:

0.125/0.75 = 0.75x/0.75

0.17 = x

For 75% syrup, add 0.17 lb of water; the total mass is 0.17+0.5 = 0.67 lb.

For 1.5% syrup, set the equation equal to 0.015:

Using the distributive property,

0.5 = 0.015(0.5) + 0.015(x)

0.5 = 0.0075 + 0.015x

Subtract 0.0075 from each side:

0.5-0.0075 = 0.0075 + 0.015x - 0.0075

0.4925 = 0.015x

Divide both sides by 0.015:

0.4925/0.015 = 0.015x/0.015

32.8 = x

For 1.5% syrup, use 32.8 lb of water; the total mass is 32.8+0.5 = 33.3 lb.

I hope this is right and have a good day

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3 years ago

Read 2 more answers

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e-lub [12.9K]

Answer:

a number, t, increased by 23

a number, t, plus 23

Step-by-step explanation:

Have a lovely rest of your day/night, and good luck with your assignments! ♡

~ ren ⚘

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3 years ago