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3 years ago

you have a work meeting that starts at 1:15 pm. you arrived at 12:53 pm. how many minutes early were you?

1 answer:

3 0

I totally forgot that I am having meeting at my work place. All of sudden, I remembered that meeting through a hint given by my colleague while having discussion about our project work. I have to present a topic which I didn't prepare yet. Meeting is at 1.15pm. OMG! It's already 12.30 pm. Within few minutes I went to the meeting place with my topic. When I entered the meeting hall, the time was 12.53pm. I was happy to know that I arrived 22 minutes earlier.

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Use the diagram to solve for segments SW and WQ. Show your work and/or explain how you determined the answer

Minchanka [31]

The intersecting chords theorem states that whenever two chords intersect, the product of their pieces is constant.

So, in this case, we have

$\overline{RW}\cdot\overline{WP}=\overline{SW}\cdot\overline{WQ}$

Plugging your values, we have

$8\cdot 9 = 6x \cdot 12x \iff 72=72x^2 \iff x^2=1$

This equation has solutions $x=\pm 1$ , but we can't choose $x=-1$ , because it would lead to

$\overline{SW}=-6,\quad\overline{WQ}=-12$

So, the only feasible solutions is $x=1$

5 0

3 years ago

How to solve 6x+3=5x+10

laila [671]

$6x+3=5x+10 \\\\ 6x-5x=10-3 \\\\ \boxed{x=7}$

7 0

3 years ago

Read 2 more answers

Identify a sequence of transformation that maps triangle ABC onto triangle A"B"C" in the image below.

Vladimir79 [104]

I'd go with: D. clockwise 90 rotation; reduction

(Hope I helped :D

5 0

3 years ago

Read 2 more answers

Please help me with my homework.

Blababa [14]

Answer:

-3x + 6

Step-by-step explanation:

-3(x - 2) to find the equivalent of this expression, we need to multiply inside the parenthesis with -3 (with both x and -2)

-3(x - 2 = -3x + 6 (two negative expressions multiplied results in positive)

3 0

3 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago