you have a work meeting that starts at 1:15 pm. you arrived at 12:53 pm. how many minutes early were you?

1 answer:

3 0

I totally forgot that I am having meeting at my work place. All of sudden, I remembered that meeting through a hint given by my colleague while having discussion about our project work. I have to present a topic which I didn't prepare yet. Meeting is at 1.15pm. OMG! It's already 12.30 pm. Within few minutes I went to the meeting place with my topic. When I entered the meeting hall, the time was 12.53pm. I was happy to know that I arrived 22 minutes earlier.

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Vinvika [58]

Hi there! Hopefully this helps!

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<em>Remember: When the numerator and denominator both are positive integers or both are negative integers, it is a positive rational number. When either the numerator or the denominator is a negative integer, it is a negative rational number.</em>

(-1/-3) Positive Rational Number.

(+1/-3) Negative Rational Number.

(-2/+3) Negative Rational Number.

(+1/+3) Positive Rational Number.

(+2/-3) Negative Rational Number.

(-1/+3) Negative Rational Number.

(-2/-3) Positive Rational Number.

(+2/+3) Positive Rational Number.

4 0

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7 0

3 years ago

The variables x and y are inversely proportional, and y = 2 when x = 3. What is the value of y when x = 9?

Nina [5.8K]

Answer:

$\huge \purple{ \boxed{ y = \frac{2}{3} }}$

Step-by-step explanation:

Since, the variables x and y are inversely proportional.

$\therefore \: y \: \: \alpha \: \: \frac{1}{x} \\ \implies \: y = \frac{k}{x} \\ (k = constant) \\ \implies \: xy = k ...(1)\\ plug \: y = 2, \: \: x = 3 \: in \: equation \: (1) \\ we \: find \\ 2 \times 3 = k \\ k = 6 \\ plug \:k = 6 \: in \: equation \: (1) \\ xy = 6 \\ (this \: is \: the \: equation \: of \: variation) \\ when \: x = 9 \: \: y =? \\ \\ 9y = 6 \\ y = \frac{6}{9} \\ \huge \red{ \boxed{ y = \frac{2}{3} }}$