Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer: $338 decrease. $4,862 total at the end of the year.
Step-by-step explanation: 6.5% of $5,200 is $338. $,5,200 - $338 = $4,862
Hope this helps!
To find the x-int., let y = 0 and solve for x: 13x = 6, so x = 6/13: (6/13, 0)
To find the y-int., let x =0 and read off the y-int: (0, -6)
Answer:
(2, 6)
Step-by-step explanation:
if you meant for both of the y to be the same then this should be right
Answer:
answer is 456986973*'/96659