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3 years ago

Solve the system by substitution.

Mathematics

2 answers:

mezya [45]3 years ago

8 0

Answer:

(2, 6)

Step-by-step explanation:

if you meant for both of the y to be the same then this should be right

Roman55 [17]3 years ago

8 0

Answer:

(2,6)

Step-by-step explanation:

*this is actually elimination*

1st- Turn both of them into standard form.

y=9x-12 ---> 9x-y=12

y=3x --> 3x-y=0

Multiply 9x-y=12 by -1

-9x+y=-12

3x-y=0

-6x=-12

divide by 6

x=2

Plug 2 into the first equation

9(2)-y=12

18-y=12

Cancel out 18 by subtracting -18 to both sides

-y=-6

divide by -1

y= 6

Answer: (2,6)

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Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$