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fenix001 [56]
3 years ago
12

What one should I choose I'm stumped ??

Mathematics
2 answers:
Karolina [17]3 years ago
8 0
The second one is the best answer in my opinion i'm not sure.
Salsk061 [2.6K]3 years ago
8 0
The second one is the answer bc each square is a unit, so if you find the place of each letter you would find the option number 2 is the correct answer.
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If two angles are congruent, then they are vertical angles? True or False. If true explain your reasoning. If false, give an cou
Bond [772]
This statement is false as all vertical angles are considered congruent but not all congruent angles are considered vertical angles. Any obtuse or acute angle may be considered congruent. If the angle from point A to B is 110 and the angle between B to C is 110 as well then they are congruent
3 0
3 years ago
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Solve the inequality for w.<br><br> 20 ≥ - 4w<br><br> Simplify your answer as much as possible.
Oksanka [162]

Answer:

w\geq-5

Step-by-step explanation:

-4w\leq20

4w\geq-20

w\geq-5

8 0
3 years ago
Solve the inequality<br> 2x&lt;24
DanielleElmas [232]

Answer:

x<2

Step-by-step explanation:

Divide 24 by 12 to get 2.

6 0
3 years ago
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Which is the equation of a line that is parallel to 2x + 5y = 4 and goes through the point (5, –4) ?
barxatty [35]

we know that

if two lines are parallel

then

their slopes are equal

Step 1

Find the slope of the line 2x + 5y = 4

2x + 5y = 4------> 5y=4-2x-----> y=(4/5)-(2/5)x------> slope m=(-2/5)

step 2

with m=-2/5 and the point (5, –4) find the equation of the line

y-y1=m*(x-x1)------> y+4=(-2/5)*(x-5)----> y=(-2/5)x+2-4

y=(-2/5)x-2

therefore

the answer is the option D

4 0
3 years ago
Read 2 more answers
PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

3 0
3 years ago
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