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Mariana [72]
3 years ago
7

3(x+2)=3x+4 how to slove it

Mathematics
2 answers:
Mice21 [21]3 years ago
5 0
3(x+2)=3x+4
Step 1: Simplify both sides of the equation.
3(x+2)=3x+4(3)(x)+(3)(2)=3x+4
(Distribute)
3x+6=3x+4
Step 2: Subtract 3x from both sides.
3x+6−3x=3x+4−3x6=4
Step 3: Subtract 6 from both sides.
6−6=4−6
the answer is -2

hope this helped :)
Makovka662 [10]3 years ago
3 0

Answer:

No solution

Step-by-step explanation:

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Delvig [45]
<span>The answer is B.

The reason being is that in this option they have set both sides of the equation separately equal to y. Since they are equal to each other, they would both have to be equal to an unknown y. This would look like this.
y = 1/4x - 3
y = 1/2x + 8.

Then to remove the fractions in each, they multiplied by the denominator associated with x. So, you multiply the first equation by 4.
4y = x - 12.
Then they solve for the numerical value at the end.
4y - x = -12.

You can do the same with the second equation.
y = 1/2x + 8
2y = x + 16
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These are now the two equations above. </span>
6 0
3 years ago
A. A 5in radius ball is in a
abruzzese [7]

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

V_{ball} = \frac{4}{3} \pi r^3

V_{ball} = \frac{4}{3} \times 3.14(5)^3

V_{ball} = \frac{4}{3} \times 3.14\times 125

V_{ball} = \frac{1,570}{3}\: In^3

V_{box} =l^3

V_{box} =(10)^3

V_{box} =1000\: In^3

Percentage of the space in the box occupied by the ball

= \frac{V_{ball}}{V_{box} } \times 100

= \frac{\frac{1,570}{3}}{1000} \times 100

= \frac{1570}{3000} \times 100

= \frac{157}{3}

= 52.33\%

5 0
3 years ago
You are flying a kite on a line that is 350 feet long. Let's suppose the line is perfectly straight (it never really is) and it
aliina [53]

Answer:

We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.

And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.

This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°

A = 90° - 65° = 25°

Then the altitude of the kite is the adjacent cathetus to this angle.

We can use the relation:

sin(A) = Adjacent cathetus/hypotenuse.

Sin(25°) = X/350ft

Sin(25°)*350ft = X = 147.9m

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