Answer
I think that there's 5 but i'm probably wrong so I wouldn't use my answer if I were you
Answer:
0.6173 = 61.73% probability that the product operates.
Step-by-step explanation:
For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
An electronic product contains 48 integrated circuits.
This means that 
The probability that any integrated circuit is defective is 0.01.
This means that 
The product operates only if there are no defective integrated circuits. What is the probability that the product operates?
This is P(X = 0). So


0.6173 = 61.73% probability that the product operates.
Vertex form uses the following formula:

Identify the values of h and k in your function:


The vertex is found with the following point:


The vertex will be found at
(-5, -28).
Plug in 3 for x so
2(3)+2
6+2=
8
The evaluation is 8