m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
Answer:
-27,0
Step-by-step explanation:
I think, not entirely sure tho.
Answer:
Step-by-step explanation:
The tangent is the Opposite over the Adjacent sides. (SOHCAH<u>TOA</u>).
Opposite/Adjacent = 4/9 = 0.44444
The angle whose tangent is 0.44444 is 23.96 or 24 degrees (round to nearest tenth).
It's 11 because 6+5=11 other words it means it's 11 squares away
Answer:
90°
Step-by-step explanation:
x + 37 + 53 = 180 (ANGLE SUM PROPERTY)
x + 90 = 180
x = 180-90
x = <u>90°</u>