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telo118 [61]
3 years ago
14

1 a-2a-{3a-(4a-5)} i need help plz and on this one to 13(5-t)-(5-t)-12(5-t)

Mathematics
1 answer:
KengaRu [80]3 years ago
8 0

Answer:

1. -5

2. 0

Step-by-step explanation:

<em>1.</em> Distribute the Negative Sign:

=a−2a+−1(3a−(4a−5))

=a+−2a+−1(3a)+−1(−4a)+(−1)(5)

=a+−2a+−3a+4a+−5

Combine Like Terms:

=a+−2a+−3a+4a+−5

=(a+−2a+−3a+4a)+(−5)

Answer:

=−5

<em>2. </em>Distribute:

=(13)(5)+(13)(−t)+−5+t+(−12)(5)+(−12)(−t)

=65+−13t+−5+t+−60+12t

Combine Like Terms:

=65+−13t+−5+t+−60+12t

=(−13t+t+12t)+(65+−5+−60)

Answer:

=0

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Answer: (2.54,6.86)

Step-by-step explanation:

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Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

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The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

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We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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