Answer: The answer is either letter A or letter D
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Hint 1: Find the direction cosines of AB and BC. Then take their dot product. This will give the cosine of the angle between AB and BC.
Hint 2: The Direction Cosines of PQ, P(x1,y1,z1) and Q(x2,y2,z2), are (±x2−x1(x2−x1)2+(y2−y1)2+(z2−z1)2√,±y2−y1(x2−x1)2+(y2−y1)2+(z2−z1)2√,±z2−z1(x2−x1)2+(y2−y1)2+(z2−z1)2√)
Edit: The Dot Product works iff the lines intersect.
B is the intersect point , doesn't matter if it's in 2D or 3D – Ali Apr 28 '18 at 5:52
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Lines in dimension three do not have to intersect. We find their direction vectors to see if they are parallel.
Note that
AB→=<x2−x1,y2−y1,z2−z1>
and
BC→=<x3−x2,y3−y2,z3−z2>
These vectors are the direction vectors are your lines.
The dot product
AB→.BC→
along with the norms of these vectors determine the angle between the lines if they intersect at all.
cosθ=AB→.BC→||AB||.||BC||
Step-by-step explanation: This is for the picture
Center: (0, 0)
Width: 10
Angle: 0 rad
Height: 6.8
Opacity: 1
So,
1. Graph each inequality separately.
2. Choose a test point to determine which side of the line needs to be shaded.
3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)
As for the system of inequalities we say it's unbounded.
Answer:
Step-by-step explanation:
(a+b)(a-b)
-ab+ab-