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aleksandrvk [35]
1 year ago
7

A solid cylinder of iron whose diameter is 18 cm and height 12 cm is melted and turned into a solid sphere. Find the diameter of

the sphere so formed​
Mathematics
1 answer:
finlep [7]1 year ago
6 0

Answer:

Diameter of sphere = 18 cm

Step-by-step explanation:

<h2>Volume of Cylinder and Sphere:</h2><h3> Cylinder:</h3>

     Diameter = 18 cm

                  r = 18÷ 2 = 9 cm

                 h = 12 cm

\sf \boxed{\bf Volume \ of \ cylinder = \pi r^2h}

                                    = π * 9 * 9 * 12 cm³

<h3>Sphere:</h3>

  \sf \boxed{\text{\bf Volume of sphere = $\dfrac{4}{3} \pi r^3$}}

Solid cylinder is melted and turned into a solid sphere.

Volume of sphere = volume of cylinder

 \sf \dfrac{4}{3}\pi r^3 = \pi *9*9*12

      \sf r^{3}= \dfrac{\pi *9*9*12*3}{4*\pi }\\\\  r^{3}=9 * 9 *3 *3\\\\\\r = \sqrt[3]{9*9*9}\\\\ r = 9 \ cm\\\\diameter = 9*2\\\\\boxed{diameter \ of \  sphere = 18 \ cm}

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Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}

Where:

y_{o} - Initial height of the ball, measured in feet.

v_{o} - Initial speed of the ball, measured in feet per second.

g - Gravitational constant, equal to -32.174\,\frac{ft}{s^{2}}.

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Given that y_{o} = 0\,ft, v_{o} = 95\,\frac{ft}{s}, g = -32.174\,\frac{ft}{s^{2}} and y = 120\,ft, the following second-order polynomial is found:

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The roots of this polynomial are, respectively:

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Both roots solutions are physically reasonable, since t_{1} represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas t_{2} represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

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