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Vilka [71]
3 years ago
12

Please help with my algebra homework and explain if you can

Mathematics
1 answer:
balandron [24]3 years ago
5 0

A= \frac{1}{2} h (x+y)

we have to solve for x , solving for x means , we have to isolate x one one side , by shifting all other variables to other side

So

A= \frac{1}{2} h (x+y)

Multiply both sides by 2

2A = h(x+y)

Divide both sides by h

2A/h = x+y

Subtract y from both sides

\frac{2A}{h}  -y =x

or

x=\frac{2A}{h}  -y

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I need help on my warm up!! pls thx!
xxMikexx [17]

Step-by-step explanation:

\tt{30.16 = 17.56 + 5x}

Swap the sides of the equation :

⤑ \tt{17.56 + 5x = 30.16}

We want to remove the 17.56 first.

Since the original equation is 17.56 , we are going to use the opposite operation and subtract 17.56 from both sides :

⤑ \tt{5x + 17.56 - 17.56 = 30.16 - 17.56}

Simplify. 17.56 - 17.56 = 0 on the left. 30.16 - 17.36 = 12.6 on the right.

⤑ \tt{5x = 12.6}

Then, we need to think about how to remove the coefficient 5. Since the opposite of multiplication is division , I am going to divide both sides by 5.

⤑ \tt{ \frac{5x}{5}  =  \frac{12.6}{5}}

Simplify. 5/5 = 1 on the left and 12.6/5 = 2.52 on the right. So, Our answer is x = 2.52.

\pink{ \boxed{ \boxed { \tt{Our \: final \: answer :  \underline{ \underline{ \bold{ \tt{x = 2.52}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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7 0
3 years ago
-1/3x=2/5x2/3 solve this
Nat2105 [25]
I hope this helps you

8 0
3 years ago
What would the value of x be
nlexa [21]

Answer:

65°

Step-by-step explanation:

The sum of the interior angles of a quadrilateral is 360 degrees.

65+115+115=295

360-295=65

Answer: 65°

8 0
3 years ago
Read 2 more answers
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
2. En la ciudad de Quito, en la temporada fría, se registran temperaturas que van desde los 5 °C hasta los 18 °C. En la temporad
natulia [17]

Answer:

(See explanation below for further detail/Véase la explicación abajo para mayores detalles)

Step-by-step explanation:

(This exercise is written in Spanish and explanations will be held in such language)

a) Las temperaturas quedan representadas a continuación:

Quito - Temporada Fría

Intervalo

5 ^{\circ}C \leq t \leq 18^{\circ}C (Este intervalo indica si el dato puede pertenecer a la temporada fría)

Conjunto

C = \{\forall t \in \mathbb {R}| 5 \leq t \leq 18\} (Este conjunto acumula todo el registro de las temperaturas de la temporada fría)

Quito - Temporada Cálida

Intervalo

4 ^{\circ}C \leq t \leq 30^{\circ}C (Este intervalo indica si el dato puede pertenecer a la temporada cálida)

Conjunto

H = \{\forall t \in \mathbb {R}| 4 \leq t \leq 30\} (Este conjunto acumula todo el registro de las temperaturas de la temporada cálida)

b) La temperatura de la ciudad de Quito pertenece esencialmente a dos intervalos:

Intervalo de Temporada Fría:

5 ^{\circ}C \leq t \leq 18^{\circ}C

Intervalo de Temporada Cálida:

4 ^{\circ}C \leq t \leq 30^{\circ}C

c) Toda temperatura mayor o igual que 4 °C y menor o igual que 30 °C.

d) Temperaturas mayores o iguales a 5 °C y menores o iguales a 18 °C.

e) Temperaturas mayores o iguales a 4 °C y menores o iguales a 30 °C.

6 0
3 years ago
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