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Lelu [443]
3 years ago
12

In a race, a runner traveled 12 meters in

Physics
1 answer:
Nastasia [14]3 years ago
3 0
     Since it is a race, the runner start from rest, so we can use the Velocity Hourly Equation to describle yours moviment.

S=S_{o}+V_{o}t+ \frac{at^2}{2}  \\ S=\frac{at^2}{2}
 
     Entering the unknowns, we have:

S=\frac{at^2}{2} \\ 12*2=a*4^2 \\ \boxed {a=1.5m/s^2}

Number 2

If you notice any mistake in my english, please let me know, because i am not native.

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Desde el balcón de un edificio se deja caer una manzana y llega a la planta baja en 5 s. ¿Desde qué piso se dejó caer, si cada p
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I will answer this in English.

We know that the apple needs 5 seconds to reach the ground.

Each floor of the building has a height of 2.88m.

Now, when we drop something, the only force acting on the object is the gravitational one, so the acceleration of the apple is:

a = -g

for the velocity, we integrate the acceleration over time, and as the apple is dropped, we do not have any initial velocity, so we do not have a constant in the integration:

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i will use g = 9.8m/s^2

0 = (-4.9m/s^2)*(5s)^2 + H  

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