Explanation :
Corrosion is the process of conversion of metal into its oxides, hydroxides and sulfides.
Rusting of iron is the process of corrosion in metals. Iron objects react with oxygen in the air and turned reddish. This reddish covering is Rust.
where, is iron
is oxygen present in atmosphere
and is rust or Ferric oxide.
In the given equation, and both are reactants and is a product.
Answer:
The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.
Explanation:
Given that,
Velocity of ship = 2.00 m/s due south
Velocity of boat = 5.60 m/s due north
Angle = 19.0°
We need to calculate the component
The velocity of the ship in term x and y coordinate
The velocity of the boat in term x and y coordinate
For x component,
Put the value into the formula
For y component,
Put the value into the formula
We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat
For x component,
Put the value into the formula
For y component,
Put the value into the formula
Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.
Answer:
- Here we use the conservation of momentum theorem.
- m stands for mass, and v stands for velocity. The numbers refer to the respective objects.
- m1v1 + m2v2 = m1vf1 + m2vf2
- Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.
- m1v1 + m2v2 = vf(m1 + m2)
<u>Let’s substitute in our givens.</u>
(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)
I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.
Note that I have considered the bullet’s velocity to be in the positive direction,
The answer is vf = 0.280 m/s
Answer:
6.92*10^4 N/m
Explanation:
F = kx
=> k = F/x and force F = weight = mg, so
k = mg/x
= (92.5*9.8)/0.0131
= 6.92*10^4 N/m
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.