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3 years ago

Describe the path of an electrical impulse as it moves through a neuron

Physics

1 answer:

maksim [4K]3 years ago

8 0

Answer & Explanation:

The nerve impulses start in the dendrites then moves down the axon starting in the axon. Nerve impulses speed up the myelin sheath. Then through the nodes of ranvier speeding up action potential then at the axon terminal the electrical impulse goes through the synapse through electrical then chemical with neurotransmitters and electrical again back to a dendrite.

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In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the

Lerok [7]

Answer:

Minimum speed will be equal to 2.213 m/sec

Explanation:

We have given radius of the r = 2 m

Coefficient of friction $\mu =0.25$

At minimum speed frictional force will be equal to centripetal force

So $\mu mg=\frac{mv^2}{r}$

$\frac{v^2}{r}=\mu g$

$v=\sqrt{\mu rg}=\sqrt{0.25\times 2\times 9.8}=2.213m/sec$

So the minimum speed will be equal to 2.213 m/sec

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3 years ago

A 350 gram mass is tied to a string and spin in a horizontal circle with a radius of 11.0cm.The speed of the mass is held consta

SSSSS [86.1K]

Explanation:

a) The angular speed omega is given defined as

omega = #rev/period = 1 rev/(0.6 s) = 1.7 rev/s

= (1.7 rev/s)×(2pi/rev) = 10.5 rad/s

b) v = (omega)×r

= (10.5 rad/s)(0.110 m)

= 1.16 m/s

7 0

3 years ago

1. Day and Night are caused by

amid [387]

Answer : D , I know i’m correct !

8 0

3 years ago

Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially

statuscvo [17]

Answer:

Final speed is 900.06 m/s at $0.2215^{\circ}$

Solution:

As per the question:

Mass of the first asteroid, m = $15\times 10^{3}\kg$

Mass of the second asteroid, m' = $20\times 10^{3}\kg$

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, $\theta = 20^{\circ}$

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

$\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}$