Answer: £4597.82
Step-by-step explanation:
Answer:
Dimensions : 37.5 * 12.5
length : 37.5
width : 12.5
Step-by-step explanation:
let x = length and y = width
x = 3y based on info from problem
Perimeter = 2(length + width)
100 = 2(x + y)
substitute 3y for x
100 = 2(3y + y)
100 = 2(4y)
100 = 8y
y = 12.5
x = 3(12.5) = 37.5
Answer:
49
Step-by-step explanation:
∆ABC~ ∆XYZ
AB= 11 that is half of XY = 22
therefore XZ/2 = AC (base) = 32/2 = 16
and YZ /2 = BC(hypotenuse) = 44/2 = 22
(a= 11, b= 16, c= 22)
perimeter of a triangle
P = a+b+c
P= 11+16+22= 49
I believe the the correct answer would be yes. Two lines can be drawn from a point that is not collinear with a certain line that will meet the line at a right angle or 90 degree angle and at an angle of 45 degrees. We can freely draw any line that would pass through a given point and would cross a given line at any direction giving us different angles and this would include a 90 and 45 degree angle.
