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Hunter-Best [27]
3 years ago
15

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
UNO [17]3 years ago
4 0

Answer:

no solution

Step-by-step explanation:

no solution

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Can I get help on 37 please someone
GaryK [48]

Answer:

B

Step-by-step explanation:

B is the correct answer.

8 0
3 years ago
Yvette earns $3 for every 1/4 hour she works. what is her hourly rate of pay
Lunna [17]
Yvette's hourly rate of pay is $12.
3+3+3+3=12
7 0
3 years ago
Brandon makes lemon water by adding of a cup of sliced lemon to 2 cups of water. At this rate, how many cups of sliced lemon wou
siniylev [52]
B bc of the mass of the cup is 12
8 0
3 years ago
The midpoint of the coordinates (3, 15) and (20,8) is -
Nat2105 [25]

Answer:

The midpoint of the given coordinates is (\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5).

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

On substituting the given values, we get;

M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})

We can also say that M(x,y)=(11.5,11.5)

Hence The midpoint of the given coordinates is (\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5).

3 0
3 years ago
Ann believes that y= 3x (x -7) is a quadratic function. Jordan says that she is wrong because the degree (highest exponent) is n
ad-work [718]

Answer:

Ann us correct. It's a quadratic function.

Step-by-step explanation:

Given equation is,

y = 3x(x - 7)

By converting this equation into the standard quadratic equation,

y = 3x² - 21x

Highest exponent of the polynomial equation is 2 (Exponent of highest degree variable x²). This decides that the given function is a quadratic function.

Therefore, Ann is correct. It's a quadratic function.

5 0
3 years ago
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