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3 years ago

Ashley posts 17 status updates on her Facebook wall each day . Roberto posts 21 status updates on his Facebook wall each day .

Mathematics

2 answers:

shutvik [7]3 years ago

4 0

Let x be the number of days.

If Ashley posts 17 status updates each day, then after x days Ashley posts 17x status updates.

If Roberto posts 21 status updates each day, then after x days Roberto posts 21x status updates.

Part A. The combined number of posts for Ashley and Roberto after x days is:

17x+21x.

Part B. The difference between number of posts for Ashley and Roberto after x days is:

21x-17x.

Anarel [89]3 years ago

3 0

A= 17x
R= 21x
combined: 17x+21x

21x-17x

please vote my answer brainliest. thanks!

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Question 5 (1 point)

Damm [24]

Answer:

36 and 49

Step-by-step explanation:

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3 years ago

The total number of? restaurant-purchased meals that the average person will eat in a? restaurant, in a? car, or at home in a ye

zmey [24]

Answer:

The number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

Step-by-step explanation:

Suppose, the number of meals eaten in a restaurant is $x$ , in a car is $y$ and at home is $z$

The total number of meals eaten in a restaurant, in a car or at home is given as 163. So, the first equation will be......

$x+y+z=163 .............................(1)$

The total number meals eaten in a car or at home exceeds the number eaten in a restaurant by 13. So, the second equation will be......

$y+z=x+13 ................................(2)$

Twenty more restaurant-purchased meals will be eaten in a restaurant than at home. So, the third equation will be......

$x= z+20..................................(3)$

First, substituting equation (2) into equation (1), we will get........

$x+(x+13)=163\\ \\ \Rightarrow 2x+13=163\\ \\ \Rightarrow 2x=163-13=150\\ \\ \Rightarrow x=\frac{150}{2}=75$

Now plugging this $x=75$ into equation (3), we will get......

$75=z+20\\ \\ \Rightarrow z=75-20= 55$

Plugging $x=75$ and $z=55$ into equation (1) .........

$75+y+55=163\\ \\ \Rightarrow y+130=163\\ \\ \Rightarrow y=163-130=33$

So, the number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

8 0

3 years ago

What does License Ends in 28 days mean?

Ivanshal [37]

I think it means expires. I'm not sure though

4 0

3 years ago

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0

3 years ago

You owe $300 on your credit card. For every month that you fail to make a payment, your balance increases by 1%. Find a formula

Vlada [557]

Answer:

$B(t) = 300(1.01)^{t}$

Step-by-step explanation:

The balance owed after t months can be given by an exponential function in the following format:

$B(t) = B(0)(1+r)^{t}$

In which B(0) is the initial balance owed and r is the growth rate, as a decimal.

You owe $300 on your credit card. For every month that you fail to make a payment, your balance increases by 1%.

This means, respectively, that $B(0) = 300, r = 0.01$

$B(t) = 300(1+0.01)^{t}$

$B(t) = 300(1.01)^{t}$

4 0

3 years ago