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babymother [125]
3 years ago
15

Write down a number that is not a rational number. explain why.

Mathematics
1 answer:
KatRina [158]3 years ago
8 0
3.7491739193721... because rational numbers are numbers like -3 -2 -1 0 1 2 3 and decimals like 3.3333333 and 1.62162162162162 because they repeat the same numbers like a pattern, with 3 repeating or 162.The decimal 3.7491739193721... is not rational, or irrational because it is not repeating or terminating, or stopped.
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C is the correct answer homie
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How do you solve each system by graphing
abruzzese [7]

See the attached graph

<h2>Explanation:</h2>

Hello! Remember to write complete questions in order to get good and exact answers. Here you don't provide any system so I couldn't help you in an exact way, but in a general manner. When solving systems by graphing we just need to find the points of intersection of the graphs of the functions that built up the system.

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\left\{ \begin{array}{c}y=2x+3\\3y=8x+27\end{array}\right.

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3 years ago
Determine if A^-1 C=C A^-1 Given:<br><br> A^-1 C=
ryzh [129]

<em>CA </em>⁻¹ is undefined because there are more columns in <em>A </em>⁻¹ than there are rows in <em>C</em>.

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3 years ago
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A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

d_1 =6ft

There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

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5b = 55ft\ 6in - 4.5ft - 6ft

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5b = 44.5ft\ + \frac{6}{12}ft

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b = 9ft

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3 0
3 years ago
5x 2 +1=−13x−5 the two is an exponent for the 5x.
tester [92]

Answer:

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3 years ago
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