Question

What is the equation of a line passing through (-6, 5) and having a slope of 1/3?

Answer 1

The equation of a line:
$y=mx+b$
m - the slope, b - the y-intercept

The slope is 1/3, so the equation of the line is $y=\frac{1}{3}x+b$.
Plug the values (x,y)=(-6,5) of the point into the equation:
$5=\frac{1}{3} \times (-6)+b \\ 5=-2+b \\ 5+2=b \\ b=7 \\ \\ \boxed{y=\frac{1}{3}x+7}$