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Musya8 [376]
3 years ago
7

Josh drew the rectangle below and then reflected it over C D to form Rectangle A'B'C'D'. He argues that the image of the rectang

le will be in the same location as the original rectangle was. His classmate, Raquel, thinks that it wil not be. Who is correct?
Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer: Raquel

Step-by-step explanation: If you’re reflecting then obviously it’s going to be in a new spot because it flips to somewhere new

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<span>5/5 ÷ 1/2 =
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3 years ago
a student spent 15 minutes painting a 2 foot by 3 foot bulletin board. to the nearest tenth of a minute, how long did it take th
Katyanochek1 [597]
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2 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

3 0
2 years ago
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3 0
3 years ago
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