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3 years ago

What is the negative coterminal angle of 165 degrees ?

Mathematics

2 answers:

kipiarov [429]3 years ago

8 0

Answer:

-195 degrees

Step-by-step explanation:

we can subtract 360 from 165 to find the negative coterminal angle.

165-360=-195

Alex Ar [27]3 years ago

3 0

165-360=-195 so -195 is the conterminal angle

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Which of these scales are equivalent to 3 cm to 4 km?

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Answer: The answer is A and D

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3 years ago

What is two numbers that when added equal 25 but when multiplied equal negative 200

Law Incorporation [45]

Well lets look at it lets find multiples that equal 200 when multiplied first to get rid of extra work

so i just took a couple of guesses and lined them up
i got really close when i did this one
-200/30 = -6.666666667
30 + 6.666666667 = 23.33333333
see not quite there almost 25 but not far enough
so ill try to move the numbers around little by little.
-200/29.5 = -6.779661017
29.5 + -6.779661017 = 22.72033898
okay honestly after i finished this trial i wasn't sure if i was thinking straight because i completely didnt think about which way i needed to go so now i pinched myself and this time we might head the right way lol
-200/30.5 = -6.557377049
30.5 + -6.557377049 = 23.94262295
so obviously we need to move up alittle more
-200/31 = -6.451612903
31 + -6.451612903 = 24.5483871
HEY LOOK WE ARE ALMOST THERE!! lets try some more;)
-200/31.5 = -6.349206349
31.5 + -6.349206349 = 25.15079365
see we are at 25! but lets try to get rid of as many numbers behind it as possible.
-200/31.4 = -6.369426752
31.4 + -6.369426752 = 25.03057325
getting closer...
-200/31.39 = -6.371455878
31.39 + -6.371455878 = 25.01854412
what does this mean? this means we can go lower... sooo here we go
-200/31.38 = -6.373486297
31.38 + -6.373486297 = 25.0065137
i guess we can try lower..
-200/31.37 = -6.375518011
31.37 + -6.375518011 = 24.99448199
wait! before you leave! try 31.379
-200/31.379 = -6.37368941
31.379 + -6.37368941 = 25.00531059
okay so yes, i am taking the very long way but good comes to those with patience:D lets try making the third place after the decimal a little bit lower
-200/31.377 = -6.374095675
31.377 + -6.374095675 = 25.00290432
yes we can take it lower so lets make it the best answer
-200/31.376 = -6.374298827
31.376 + -6.374298827 = 25.00170117
i pray this be over soon^ lets try again....
-200/31.375 = -6.374501992
31.375 + -6.374501992 = 25.00049801
okay im a perfectionist... sooo lets go lower
-200/31.374 = -6.37470517
31.374 + -6.37470517 = 24.99929483
okay so we went to low on the third place. and of course i am moving to the fourth place...
-200/31.3749 = -6.374522309
31.3749 + -6.374522309 = 25.00037769
okay we can move lower on that place....
-200/31.3748 = -6.374542627
31.3748 + -6.374542627 = 25.00025737
lets try to move this along faster...
-200/31.3746 = -6.374583262
31.3746 + -6.374583262 = 25.00001674
every number counts literally so moving lower
-200/31.3744 = -6374623897
31.3744 + -6374623897 = 24.9997761
we gotta put a 9 on our fifth place from our decimal sooo here we go again
-200/31.37449 = -6.374605611
31.37449 + -6.374605611 = 24.9998439
OMG DO YOU UNDERSTAND WHAT THIS MEANS!!?!?!
okay that means our answer was two trials ago solved
in other words our two numbers arreee
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-6.374583262
hallelujah we are finished and if this is wrong i will pull my hair out.

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3 years ago

There are 50 kids at the park 30 of the girls what percent of the kids are boys

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Answer:

40 %

Step-by-step explanation:

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3 years ago

A farmer ordered 3/4 ton of soil. He wants to divide it evenly into 8 flower beds. How much will he have for each bed?

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3 years ago

) Use the Laplace transform to solve the following initial value problem: y′′−6y′+9y=0y(0)=4,y′(0)=2 Using Y for the Laplace tra

artcher [175]

Answer:

$y(t)=2e^{3t}(2-5t)$

Step-by-step explanation:

Let Y(s) be the Laplace transform Y=L{y(t)} of y(t)

Applying the Laplace transform to both sides of the differential equation and using the linearity of the transform, we get

L{y'' - 6y' + 9y} = L{0} = 0

(*) L{y''} - 6L{y'} + 9L{y} = 0 ; y(0)=4, y′(0)=2

Using the theorem of the Laplace transform for derivatives, we know that:

$\large\bf L\left\{y''\right\}=s^2Y(s)-sy(0)-y'(0)\\\\L\left\{y'\right\}=sY(s)-y(0)$

Replacing the initial values y(0)=4, y′(0)=2 we obtain

$\large\bf L\left\{y''\right\}=s^2Y(s)-4s-2\\\\L\left\{y'\right\}=sY(s)-4$

and our differential equation (*) gets transformed in the algebraic equation

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0$

Solving for Y(s) we get

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0\Rightarrow (s^2-6s+9)Y(s)-4s+22=0\Rightarrow\\\\\Rightarrow Y(s)=\frac{4s-22}{s^2-6s+9}$

Now, we brake down the rational expression of Y(s) into partial fractions

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4s-22}{(s-3)^2}=\frac{A}{s-3}+\frac{B}{(s-3)^2}$

The numerator of the addition at the right must be equal to 4s-22, so

A(s - 3) + B = 4s - 22

As - 3A + B = 4s - 22

we deduct from here

A = 4 and -3A + B = -22, so

A = 4 and B = -22 + 12 = -10

It means that

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

and

$\large\bf Y(s)=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

By taking the inverse Laplace transform on both sides and using the linearity of the inverse:

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}$

we know that

$\large\bf L^{-1}\left\{\frac{1}{s-3}\right\}=e^{3t}$

and for the first translation property of the inverse Laplace transform

$\large\bf L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=e^{3t}L^{-1}\left\{\frac{1}{s^2}\right\}=e^{3t}t=te^{3t}$

and the solution of our differential equation is

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=\\\\4e^{3t}-10te^{3t}=2e^{3t}(2-5t)\\\\\boxed{y(t)=2e^{3t}(2-5t)}$

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3 years ago