Glucose,fructose,and sucrose are all carbohydrates.what elements make up all carbohydrates

Which of the following leads to new discoveries and new series?

Tema [17]

Answer:

I think it's letter C or A

5 0

2 years ago

How could the movement of tectonic plates create another supercontinent like Pangaea

Margaret [11]

<span>When the landmasses are again collected together in a specific area

The Pangea theory supports the theory of plate tectonics because it is based on the idea that all the present continents were one super-continent. For reasons still unknown, the super-continent got separated and created separate smaller continents. This theory also supports the fact that this movement will continue until the day arrives when all the smaller continents will again merge in a different configuration to create another super-continent. </span>

4 0

3 years ago

How many arc seconds are in a degree

Andrews [41]

3600, PLEASE MARK AS BRAINLIEST!!!

3 0

3 years ago

if a mutation occurs in the somatic tissue, approximately how many of the gametes will carry the mutation?

Mrac [35]

None: Only those mutations that occur in the germ line and result in gametes will have a chance of being passed on to progeny. An alteration in DNA that occurs after conception.

Somatic mutations can occur in any of the body's cells except germ cells (sperm and egg) and are therefore not passed on to children. These alterations can (but not always) cause cancer or other diseases. Mutations in somatic cells are called somatic mutations. Because they do not occur in the cells that give rise to gametes, the mutation is not transmitted to the next generation sexually. Human somatic cells have 46 chromosomes: 22 pairs and 2 sex chromosomes that may or may not form a pair. This is the 2n or diploid condition. Human gametes have 23 chromosomes, each of 23 unique chromosomes, one of which is a sex chromosome. Somatic cells are the cells in the body other than sperm and eggs (called germ cells). In humans, somatic cells are diploid, meaning they contain two sets of chromosomes, one inherited from each parent. Mutations in a somatic cell occur in somatic cells and are transmitted by mitosis, resulting in cancer. However, mutations in a gamete are passed on by meiosis, resulting in mutated offspring. A genetic mutation occurs during DNA replication, and chromosomal mutations occur during meiosis.

To learn more about alteration please click on below link

brainly.com/question/2211559

#SPJ4

3 0

1 year ago

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl

nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be = p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

P p

P PP Pp

p Pp pp

From the punnet square above, we have the following cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: $Pr(G)=\frac{3}{4}$

the probability for the white plant (pp) will be: $Pr (W)= \frac{1}{4}$

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

$Pr(4G2W)$ = $(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

The probability includes the use of permutation:

$Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= $15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = $\frac{1}{4}$

The probability that 6 seeds will consist of all white seeds will be = $(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of 5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White and 1 Green Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

$Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6$

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

$Pr(6seeds)=(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds = 0.000732 + 0.000244

= 9.76 × 10⁻⁴

= 0.000976

≅ 0.001

3 0

3 years ago