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mihalych1998 [28]
3 years ago
8

Find the equation of a line that goes through points (2, 4) and (6, 8).

Mathematics
1 answer:
Ann [662]3 years ago
8 0
Y=-x-3 is the answer I believe
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A vcr and tv were bought for 8000 each. The shopkeeper made a loss of 4 per cent on vcr and 8 per cent prophit on the tv. Find t
aleksley [76]

Answer:

  2% gain

Step-by-step explanation:

We assume the shopkeeper bought the appliances at the indicated prices, and that gain is computed on the basis of that cost price.

Since the base cost is the same for each appliance, the percentages can be added directly to find the percentage gain on 8000. However, the shopkeeper's total outlay was 16000, not 8000, so the final gain percentage is half of that total.

  gain percent = (-4% + 8%)/2 = 2%

_____

If you want to see the actual numbers:

  Loss on VCR = 4% × 8000 = 320.

  Gain on TV = 8% × 8000 = 640.

Total gain on 16000 is -320 +640 = 320. As a percentage, that is ...

  320/16000 × 100% = 2%

7 0
3 years ago
3 red balls, 4 white balls, and 1 green ball are in a bag. Balls are drawn without replacement. Find the probability that the re
jolli1 [7]

The probability that the red balls can be drawn before the green ball is drawn is 3/8.

<h3>What is Probability?</h3>

The probability is the measure of the likelihood of an event to happen.

Given:

red balls= 3

white balls = 4

green balls = 1

So, Probability of red balls

=3/8

Probability of green balls

=1/7

Learn more about probability here:

brainly.com/question/14546377

#SPJ1

7 0
2 years ago
Multiply and simplify. 3xy4z2⋅5x2yx
Olenka [21]
I think the answer is 15x^4y^5z^2
4 0
4 years ago
Read 2 more answers
Help a girl out pleaseeee!!
fiasKO [112]
Spinal Cord

hope this helps
7 0
3 years ago
Read 2 more answers
A game is played with the following rules. Two ordinary number cubes, each with six sides labeled 1 to 6, are rolled. After each
Marysya12 [62]
Answer: - 0.28


Explanation:

1) Expected value: is the weighted average of the values, being the probabilities the weight.

That is: ∑ of prbability of event i × value of event i.

In this case: (probability of getting 2 or 12) × (+6) + (probability of gettin 3 or 11) × (+2) + (probability of any other sum) × (-1).


2) Sample space:

Sum              Points awarded
    
1+ 1 = 2              +6

1 + 2 = 3             +2

1 + 3 = 4             -1

1 + 4 = 5             -1

1 + 5 = 6             -1

1 + 6 = 7             -1

2 + 1 = 3             +2

2 + 2 = 4             -1

2 + 3 = 5             -1

2 + 4 = 6             -1

2 + 5 = 7             -1

2 + 6 = 8             -1

3 + 1 = 4             -1

3 + 2 = 5             -1

3 + 3 = 6             -1

3 + 4 = 7             -1

3 + 5 = 8             -1

3 + 6 = 9             -1

4 + 1 = 5             -1

4 + 2 = 6             -1

4 + 3 = 7             -1

4 + 4 = 8            -1

4 + 5 = 9            -1

4 + 6 = 10          -1

5 + 1 = 6            -1

5 + 2 = 7            -1

5 + 3 = 8            -1

5 + 4 = 9            -1

5 + 5 = 10          -1

5 + 6 = 11          +2

6 + 1 = 7            -1

6 + 2 = 8            -1

6 + 3 = 9            -1

6 + 4 = 10          -1

6 + 5 = 11          +2

6 + 6 = 12          +6


2) Probabilities

From that, there is:
- 2/36 probabilities to earn + 6 points.
- 4/36 probabilites to earn + 2 points
- the rest, 30/36 probabilities to earn - 1 points


3) Expected value = (2/36)(+6) + (4/36) (+2) + (30/36) (-1) = - 0.28
4 0
3 years ago
Read 2 more answers
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