Find the equation of a line that goes through points (2, 4) and (6, 8).
1 answer:
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Answer:
Slope = 2
y-intercept = 1
x-intercept = -0.5
Standard Form ⇒ y - 2x = 1
Step-by-step explanation:
write the equation of the line through (-2 , -3) and (0,1)
The general form of the line is y = mx + c
Where m is the slope and c is the y-intercept
The slope m = (y₂ - y₁)/(x₂ - x₁) = (1 - [-3])/(0 - [-2]) = 4/2 = 2
∴ y = 2x + c
By substitution with the point (0,1) to find c
1 = 2 *0 + c
c = 1
∴ y = 2x + 1
Or y - 2x = 1 ⇒Standard Form
Also,
See the attached figure which represents the graph of the line y - 2x = 1
