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2 years ago

The first term of a geometric sequence is 1 and its common ratio is 6. What is the sixth term?

Mathematics

1 answer:

Mariulka [41]2 years ago

4 0

Answer:

c. 7776

Step-by-step explanation:

1, 6, 36, 216, 1296, 7776

Therefore, c. 7776

I hope this helped and have a good rest of your day!

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What is the second term in the binomial expansion of (2r-3s)12?

Reptile [31]

$(a+b)^n=\displaystyle\sum_{k=0}^n\binom nka^{n-k}b^k$

where $\dbinom nk=\dfrac{n!}{k!(n-k)!}$ . The second term of the expansion occurs when $k=1$ .

So the second term of the expansion of $(2r-3s)^{12}$ is

$\dbinom{12}1(2r)^{12-1}(-3s)^1=12(2r)^{11}(-3s)=-73728r^{11}s$

5 0

3 years ago

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The table represents the function (x) = 2x+1<br> Which value goes in the empty cell?

frozen [14]

Answer:

8 maybe

Step-by-step explanation:

My guess but if it is not Sorry

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3 years ago

A box with a square base and no top is to be made from a square piece of carboard by cutting 4 in. squares from each corner and

Lunna [17]

Answer:

$C=27inch\ by\ 27inch$

Step-by-step explanation:

Squares $h=4inch$

Volume $v=1444in^3$

Generally the equation for Volume of box is mathematically given by

$V=l^2h$

$1444=l^2*4$

$l^2=361$

$l=19in$

Since

Length of cardboard is

$l_c=19+4+4$

$l_c=27in$

Therefore

Dimensions of the piece of cardboard is

$C=27inch\ by\ 27inch$

7 0

2 years ago

PLEASE HELP ILL MAKE YOU BRAINLIEST!!!!<br><br>What is the length of line segment MQ?

Salsk061 [2.6K]

The length is 11 units. x3

7 0

3 years ago

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Write the standard form of the line that passes through (-1,-3) and (2,1).

kobusy [5.1K]

Answer:

Step-by-step explanation:

$\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\$

$\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\$

Convert equation to standard form

$y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5$

5 0

3 years ago