Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
Answer:
7y+6
Step-by-step explanation
You have to do 2 times y first. That is 2y. Then you have to add 2y plus 5y, which is 7y. 7y plus 6 equals 7y+6.
Step-by-step explanation:
I didn't understood thr question and I'm pretty sure that u made a mistake while writing it
Answer:
the value of x in this image is 38
Step-by-step explanation:
we know that the total angles of triangles are 180, so m is 180-84=96, and 180-134=46, when added we get 142, which means the last angle is 38
The bead is in a cylindrical shape and the formula for solving the volume of a cylinder is V=pi*r²*h where "r" is the radius, "h" for the height.
We have given values such as:
r=diameter/2 = 2/2 = 1mm
h= 8mm
Solving for the volume, we have:
V=3.14*1²*8
V=24.12 mm²
