a. The moduli are coprime, so you can apply the Chinese remainder theorem directly. Let
- Taken mod 3, the last two terms vanish, and
so we need to multiply by the inverse of 2 modulo 3 to end up with a remainder of 1. Since 
, we multiply the first term by 2.
- Taken mod 4, the first and last terms vanish, and
. Multiply by the inverse of 3 modulo 4 (which is 3 because 
), then by 2 to ensure the proper remainder is left.
- Taken mod 5, the first two terms vanish, and
. Multiply by the inverse of 2 modulo 5 (3, since 
) and again by 3.
By the CRT, we have
i.e. any number 
(where 
is an integer) satisifes the system.
b. The moduli are not coprime, so we need to check for possible contradictions. If 
and 
, then we need to have 
. This basically amounts to checking that if , then we should also have 
.
The last congruence conflicts with the previous one modulo 3, so there is no solution to this system.
B is the answer it is the only othe shplape
Answer:
29
Step-by-step explanation:
Total marble = 36
Let red marbles be X
Then green marble is 4X + 1
And 4X + 1 + X = 36
5X = 36 - 1
5X = 35
X = 35/5 = 7
So, green marbles = 4X + 1
= 4(7) + 1
= 29
Answer:
208 ft^3
Step-by-step explanation:
Let the plane through the 4 ft X 4ft square at the top of the figure break the figure into 2 boxes, one has dimensions (8-7) by 3 by 4 = 1ft X 3ft X 4ft, and the other has dimensions 7 by 7 by 4 = 7ft X 7ft X 4ft.
They have volumes of (1)(3)(4) = 12 ft^3, and (7)(7)(4) = 196 ft^3, respectively, so the total volume = 12 + 196 = 208 ft^3, the answer.
