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enyata [817]
3 years ago
6

What is the electronegativity difference in the compound aluminum chloride, alcl3?

Chemistry
1 answer:
denpristay [2]3 years ago
6 0
Hello! The electronegativity difference in the compound would be 1.55. Chloride has a electronegativity of 3.0, while Aluminum has a electronegativity of 1.5. In order to find the difference, you would need to subtract the Chloride's electronegativity by the Aluminum's electronegativity. 
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Select the correct answer.
Serjik [45]

Ionic bond is a chemical bond formed by the complete transfer of electrons between two atoms. The atom that loses electrons gains a positive charge (cation) and that which accepts electrons gains a negative charge (anion). Now, electronegativity is a parameter that measures the tendency of an atom to accept electrons. In the context of ionic bonding, two elements which show a significant difference in their electronegativity values form ionic bonds.

In the given examples, the difference in electronegativity is greatest between K  and Br i.e. 0.8 and 2.8 respectively with a difference of 2.0. This also makes sense since K and Br are on the extreme ends of the periodic table. Hence, potassium with a valence electron configuration of 4s1 will lose its s electron to Br (4s24p6) and form an ionic molecule K⁺Br⁻

Ans E) potassium and bromine

8 0
3 years ago
Read 2 more answers
Determine the direction of bond polarity for each compound. Leave it blank for a nonpolar bond. Br−Br H−Cl F−CH3
NeX [460]

Answer:

For H-Cl, the direction is towards the chlorine atom

For F-CH3, the direction is towards the flourine atom.

Explanation:

The dipole moment is a vector quantity. This implies that it has both magnitude and direction.

Thus, the direction of the dipole moment always points from the positive atom towards the negative atom.

This explains the fact that it points to chlorine in HCl and points to flourine in F-CH3

8 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
Which of the following is a precipitation reaction?
erik [133]

Answer:

The precipitated are option a and d.

Explanation:

2 LiI(aq) +Hg2(NO3)2(aq)  →  Hg2I2(s) ↓ + 2 LiNO3(aq)

Cation Hg2+ 2 in the presence of iodide,  a precipitated  is formed.

Zn(s) + 2AgNO3(aq) → 2 Ag(s) ↓ +Zn(NO3)2(aq)

Zinc starts to get rid, and some white particles also stick to it. Afterwards the solution becomes cloudy and a precipitate appears, which is the solid silver

3 0
3 years ago
A Flame test is an example of chemistry property. What evidence can you use to back your statement up?
Lena [83]
The flame test is a qualitative test used in chemistry to help determine the identity or possible identity of a metal or metalloid ion found in an ionic compound. If the compound is placed in the flame of a gas burner, there may be a characteristic color given off that is visible to the naked eye. And for the proof. The flame test provided evidence that specific atoms are present in compounds by the color of the flame. The metal atoms are what is responsible for the colors during the flame test. The color of the flame will be yellow-orange because Sodium (Na) is present in all the compounds that have a yellow-orange flame. Hope this helps! Mark brainly please!
7 0
2 years ago
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