What is the equation of the line that passes through the points (3,-2) and (-1,2)
1 answer:
Answer:
A. y = -x + 1
Step-by-step explanation:
First find the slope of the two lines using the slope formula: .
Now use one of the two points; I am going to use (-1, 2).
Substitute the point and slope into the point-slope equation: y - y1 = m(x - x1).
y - (2) = -1(x - (-1))
Simplify.
y - 2 = -1x - 1
Add 2 to both sides and remove the 1 in front of the x. It is not needed.
y = -x + 1
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Answer:
Remember, a number a is a zero of the polynomial p(x) if p(a)=0. And a has multiplicity n if the factor (x-a) appear n times in the factorization of p(x).
1. Since -2 is a zero with multiplicity 1, then (x+2) is a factor of the polynomial.
2. Since 1 is a zero with multiplicity 2, then (x-1) is a factor of the polynomial and appear 2 times.
3. Since 5 is a zero with multiplicity 3, then (x-5) is a factor of the polynomial and appear 3 times.
Then, the polynomial function with the zeros described above is