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Scilla [17]
3 years ago
12

I have no idea how to even begin with this

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
We have two similar triangles, the one as a whole and the one inside of it. To calculate the height of the flagpole we can set up a proportion. First calculate the length of the base of the smaller triangle.

16.60 - 12.45 = 4.15m

The height is 1.65m, set up a proportion:

\sf\dfrac{1.65}{4.15}=\dfrac{x}{16.60}

Cross multiply:

\sf 27.39=4.15x

Divide 4.15 to both sides:

\sf x=\boxed{\sf 6.6m}

So the height of the flagpole is 6.6 meters tall.

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\displaystyle\int\frac{x+1}{\sqrt x}\,\mathrm dx=\int\frac x{x^{1/2}}+\frac1{x^{1/2}}\,\mathrm dx

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By the power rule,

=\dfrac{x^{3/2}}{\frac32}+\dfrac{x^{1/2}}{\frac12}+C

(this seems to be the step you're not getting?)

=\dfrac23x^{3/2}+2x^{1/2}+C

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x^{3/2}=x^{1/2+1}=x^{1/2}\cdot x^1

so that the final result is

\dfrac23x^{3/2}+2x^{1/2}+C=\dfrac23x^{1/2}(x+3)+C

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3 years ago
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