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Scilla [17]
3 years ago
12

I have no idea how to even begin with this

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
We have two similar triangles, the one as a whole and the one inside of it. To calculate the height of the flagpole we can set up a proportion. First calculate the length of the base of the smaller triangle.

16.60 - 12.45 = 4.15m

The height is 1.65m, set up a proportion:

\sf\dfrac{1.65}{4.15}=\dfrac{x}{16.60}

Cross multiply:

\sf 27.39=4.15x

Divide 4.15 to both sides:

\sf x=\boxed{\sf 6.6m}

So the height of the flagpole is 6.6 meters tall.

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Solve for the 3 sides
mel-nik [20]

Answer:

1. x = 2√3 or 3.46

2. y = 4√3 or 6.93

3. z = 4√6 or 9.80

Step-by-step explanation:

1. Determination of the value of x.

Angle (θ) = 60°

Opposite = 6

Adjacent = x

Tan θ = Opposite /Adjacent

Tan 60 = 6 / x

√3 = 6/x

Cross multiply

x√3 = 6

Divide both side by √3

x = 6 / √3

Rationalise

x = (6 / √3) × (√3/√3)

x = 6√3 / 3

x = 2√3 or 3.46

2. Determination of the value of y.

Angle (θ) = 60°

Opposite = 6

Hypothenus = y

Sine θ = Opposite /Hypothenus

Sine 60 = 6/y

√3/2 = 6/y

Cross multiply

y√3 = 2 × 6

y√3 = 12

Divide both side by √3

y = 12/√3

Rationalise

y = (12 / √3) × (√3/√3)

y = 12√3 / 3

y = 4√3 or 6.93

3. Determination of the value of z.

Angle (θ) = 45°

Opposite = y = 4√3

Hypothenus = z

Sine θ = Opposite /Hypothenus

Sine 45 = 4√3 / z

1/√2 = 4√3 / z

Cross multiply

z = √2 × 4√3

z = 4√6 or 9.80

8 0
3 years ago
Jill estimated she would spend $50.00 a month on clothing. However, at the end of the year she discovered she actually spent $71
RideAnS [48]
50$ per month for 12 years would mean she spent only (50 x 12) 600$ per year.

She actually spent $711, her forecast was off target by (600-7111) $111.

She exceeded her budget by $111
5 0
3 years ago
I need help on this problem really I would be grateful
leonid [27]

Answer:

Step-by-step explanation:

The answer is A

4 0
3 years ago
Find 2.4% of $109. Show work.
Alex73 [517]

Answer:

$2.62

Step-by-step explanation:

2.4\%  \: of  \: \$109 \:  \\  \\  =  \frac{2.4}{100}  \times 109 \\  \\  = 0.024 \times 109 \\  \\  =  \$2.616 \\  \\ \approx \: \$2.62

6 0
3 years ago
We have $10,000 to invest for 44 months. How much money will we have if we put the money into an account that has an annual inte
polet [3.4K]
A = p(1 + r/n)^nt
p = principal
r = rate, change to a decimal
n = number of times it is compounded per year
t = time in years
A = 10,000(1 + .055/12)^(12*(44/12))
Since the time is in months and the formulas is in years, I put the (44/12) to represent the time. This will actually simplify to 44.
A = 10,000(1 + .055/12)^(44)
A = $ 12,228.77
3 0
3 years ago
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