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Scilla [17]
3 years ago
12

I have no idea how to even begin with this

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
We have two similar triangles, the one as a whole and the one inside of it. To calculate the height of the flagpole we can set up a proportion. First calculate the length of the base of the smaller triangle.

16.60 - 12.45 = 4.15m

The height is 1.65m, set up a proportion:

\sf\dfrac{1.65}{4.15}=\dfrac{x}{16.60}

Cross multiply:

\sf 27.39=4.15x

Divide 4.15 to both sides:

\sf x=\boxed{\sf 6.6m}

So the height of the flagpole is 6.6 meters tall.

You might be interested in
Which name correctly classifies this triangle? A. right B. obtuse C. acute
sergejj [24]
Hello there!

The would be a (right angle) because this angle is not greater than, or less than 90°.

Your correct answer would be the first option. (right angle).
7 0
3 years ago
Help, and can you show your work?
Schach [20]

Step-by-step explanation:

answer A is correct

................

6 0
3 years ago
Read 2 more answers
a sample of 546 boys aged 6–11 was weighed, and it was determined that 89 of them were overweight. A sample of 508 girls aged 6–
AleksAgata [21]

Answer:

p-value:  0.6527

Step-by-step explanation:

Hello!

You have two samples to study, from each sample the weight of each child was measured and counted the total of overweight kids (x: "success") in each group:

Sample 1 (Boys aged 6-11)

n₁= 546

x₁= 89

^p₁= x₁/n₁ = 89/546 ≅0.16

Sample 2 (girls aged 6-11)

n=508

x= 74

^p= x/n = 74/508 ≅ 0.15

If the hypothesis statement is "The proportion of boys that are overweight differs from the proportion of girls that are overweight", the test hypothesis is:

H₀: ρ₁ = ρ₂

H₁: ρ₁ ≠ ρ₂

This type of hypothesis leads to a two-tailed rejection region, then the p-value will also be two-tailed. To calculate the p-value you have to first calculate the value of the statistic under the null hypothesis, in this case, is a test for the difference between two proportions:

Z=<u>      (^ρ₁ - ^ρ₂) - (ρ₁ - ρ₂)        </u> ≈ N(0;1)

    √(ρ` * (1 - ρ`) * (1/n₁ + 1/n₂))

ρ`=<u> x₁ + x₂  </u> = <u>  89+74     </u> = 0.154 ≅ 0.15

     n₁ + n₂     546 + 508

Z⁰ᵇ =<u>          (0.16-0.15) - (0)                    </u>

       √(0.15 * (1 - 0.15) * (1/546 + 1/508))

Z⁰ᵇ = 0.45

I've mentioned before that in this test you have a two-tailed p-value. The value calculated (0.45) corresponds to the right or positive tail and the left tail is symmetrical to it concerning the distribution mean, in this case, is 0, so it is -0.45. To obtain the p-value you need to calculate the probability of both values and add them:

P(Z>0.45) + P(Z<-0.45) = (1- P(Z<0.45)) + P(Z<-0.45) = (1-0.67364) + 0.32636 = 0.65272 ≅ 0.6527

p-value:  0.6527

Since there is no signification level in the problem, I'll use the most common to reach a decision. α: 0.05

Since the p-value is greater than α, you do not reject the null Hypothesis, in other words, there is no significative difference between the proportion of overweight boys and the proportion of overweight girls.

I hope it helps!

3 0
3 years ago
Look at the information below. The sum of the measures of angle M and angle R is 90°. © The measure of angle M is (5x + 10). The
kupik [55]

Answer:

Solution given;

<M=5x+10

<R=55

<M+<R=90°

<u>5</u><u>x</u><u>+</u><u>1</u><u>0</u><u>+</u><u>5</u><u>5</u><u>=</u><u>9</u><u>0</u><u>°</u><u>[</u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u>]</u>

<u>now</u><u> </u><u>solving</u><u> </u><u>it</u>

<u>5</u><u>x</u><u>=</u><u>9</u><u>0</u><u>-</u><u>6</u><u>5</u>

<u>5</u><u>x</u><u>=</u><u>2</u><u>5</u>

<u>x</u><u>=</u><u>2</u><u>5</u><u>/</u><u>5</u>

<u>x</u><u>=</u><u>5</u><u>i</u><u>s</u><u> </u><u>your</u><u> </u><u>answer</u><u>.</u>

8 0
2 years ago
There are 220 students in year 9.
olganol [36]
20% of 220 is 44 people so if you divide 220 by 2 you have 110 of each then add 44 to one and subtract 44 from the other the answer to a is 154 and the answer to b is 66
8 0
3 years ago
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