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3 years ago

I have no idea how to even begin with this

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

We have two similar triangles, the one as a whole and the one inside of it. To calculate the height of the flagpole we can set up a proportion. First calculate the length of the base of the smaller triangle.

16.60 - 12.45 = 4.15m

The height is 1.65m, set up a proportion:

$\sf\dfrac{1.65}{4.15}=\dfrac{x}{16.60}$

Cross multiply:

$\sf 27.39=4.15x$

Divide 4.15 to both sides:

$\sf x=\boxed{\sf 6.6m}$

So the height of the flagpole is 6.6 meters tall.

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Can you help me i dont know thw anwser

Margaret [11]

$\text{Let the side of square 1, square 2 and square 3 be x, y and z respectively.}\\\\\text{Given that,}\\\\\text{Perimeter of square 1,~~ p =100 units.}\\\\\text{So}~ x=\dfrac p 4 = \dfrac{100}4 =25~\text{units.}\\\\\\\text{Area of square 2, a = 225 units}^2\\\\\text{So}~y = \sqrt{a} = \sqrt {225} = 15~ \text{units.}\\\\\text{Use Pythagorean theorem to find z}^2\\\\x^2 =y^2 +z^2 \\\\\implies 25^2 = 15^2 +z^2\\\\\implies z^2 = 625 - 225 = 400\\\\\\$

$\text{Hence the area of square 3 is 400 units}^2.$

8 0

2 years ago

Read 2 more answers

The Questions above.

Sergeeva-Olga [200]

Answer:

It's B.9

Step-by-step explanation:

Because

11+9=20

20+9= 29

29+9= 38

The common difference is positive because the arithmetic sequence is increasing.

8 0

2 years ago

Read 2 more answers

Write an explicit formula for an,the Nth term of the sequence 4,12,36

Rudik [331]

Answer:

$3^{n}+3^{n-1}$

Step-by-step explanation:

Since the sequence is geometric (it multiplies the previous number each time). The nth term sequence would be $x^n + yn$

Because the sequence multiplies by 3 each time, The base number in that equation would be $3^n +yn$ .

So $3^n$ of the equation would be:
$3, 9, 27$ .

Compare the 2 equations:
4, 12, 36

3, 9 ,27

The difference between the 2 equations is: 1, 3, 9 which itself is a geometric sequence so the nth term of this new equation is: $3^{n-1}$ .

Combine these 2 equations together and you get:

$3^{n}+3^{n-1}$ .

6 0

1 year ago

AveGali [126]

Answer:

C. Robbie's glider

Step-by-step explanation:

P.S -The exact question is -

Given - Melissa and Robbie are flying remote control gliders.

The altitude of Melissa's glider, h(s), in feet, is modeled by this function, where sis time, in seconds, after launch.

m(s) = 0.4(s³ - 11s² + 31s – 1)

The altitude of Robbie's glider is modeled by function r, where sis time, in seconds, after launch.

To find - Which glider reaches the greater maximum altitude in the first 6 seconds after launch?

A. Neither glider reaches a maximum altitude on the given interval.

В. Melissa's glider

C. Robbie's glider

D. Both gliders reach the same altitude on the given interval.

Proof -

At t = 6 sec,

Melisa glider is

h(6) = 0.4((0.6)³ - 11(0.6)² + 31(0.6) – 1)

= 0.4( 0.216 - 3.96 + 18.6 - 1 )

= 0.4(13.856) = 5.5424

⇒h(6) = 5.5424

∴ we get

At t = 6 seconds, Melissa glider is at the altitude of 5.54 feet

Now,

From the figure, we can see that,

At t = 6 seconds, Robbie's glider is approximately at an altitude of 13 feet

Now,

As 13 > 5.5

So,

Robbie's glider is at maximum height in 6 seconds after the launch.

So,

The correct option is - C. Robbie's glider

8 0

2 years ago

Please help 20 POINTS problem below

Paraphin [41]

I think your answer would be A?

6 0

3 years ago