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3 years ago

Simplify -2(4-3x)/(5x-2)

Mathematics

1 answer:

Inessa05 [86]3 years ago

7 0

6x-8 / 5x-2 idk what else to say bc i can’t post without 20 characters

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How might the lack of reliable transportation for getting to a job affect your decision to take it or not

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Without reliable transportation, you could be late a lot, and get fired. That shows up when you apply for a new job, even if you get better transportation. If you don't want to get fired, you may not want to take the job.

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3 years ago

On the blueprint of a house and 35 mm represents 10 m an actual length of a living room is 9 m what is the length on the bluepri

nadya68 [22]

Answer:x 31.5 mm

Step-by-step explanation:I hope this helps

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3 years ago

Solve for www. Give an exact answer in simplified form. 53w+13 < 56w + 16

ki77a [65]

The solution will be: $w>-1$

Explanation

The given inequality is: $53w+13 < 56w + 16$

First we will subtract $56w$ from both sides. So.....

$53w+13-56w$

Now we will subtract 13 from both sides. So.....

$-3w$

Then we need to divide both sides by -3. As here we are dividing the inequality by a negative number, so we need to switch the inequality symbol. So, we will get.......

$\frac{-3w}{-3}>\frac{3}{-3}\\ \\ w>-1$

Thus, the solution will be: $w>-1$

5 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

I neeed heeellpp gooot 20 minutttteeessss leffttt

max2010maxim [7]

Answer:

its A

Step-by-step explanation:

F is the midpoint of AA' because E.G. bisects AA'.

4 0

3 years ago